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3 years ago

Parallel, PerpendicularOr NeitherY = 3x + 16x - 2y = 10

1 answer:

4 0

Since the new slope would be calculated to -3, the equations are neither parallel or perpendicular in accordance to each other.

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For each of the following integrals, indicate whether integration by substitution or integration by parts is more appropriate, o

Andrei [34K]

Answer:

a. ∫ xSinx dx

iii. integration by parts

u =x and dv= sinx

b. ∫ x⁴/(1+x³). dx

ii. neither

Long division is an option here before integration is done

c. ∫ x⁴. e^x³. dx

i. substitution

where u = x⁵

d. ∫x⁴ cos(x⁵). dx

i. substitution

where u = x⁵

e. ∫1/√9x+1 .dx

i. substitution

where u = 9x+1

6 0

3 years ago

What is the solution to the system of equations graphed below?

ale4655 [162]

Answer:

(2,-3)

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

I need help with question 10 please.

galben [10]

Answer:

You can determine which graph is the steepest by seeing which slope has a negative number. If it is negative then the slope will be steep.

Step-by-step explanation:

7 0

3 years ago

Solve the equation by completing the square

Ilya [14]

Answer:

We got the quadratic equation:

$x^2+8x-3=0$

Solving by completing the square:

$x^2+8x-3=0\\x^2+8x+16-16-3=0\\(x+4)^2-16-3=0\\(x+4)^2-19=0\\(x+4)^2=19\\x+4=\pm \sqrt{19} \\x=-4\pm \sqrt{19} \\\\x_{1} =-4+\sqrt{19} \\x_{2} =-4-\sqrt{19}$

Therefore, the answer is letter C

4 0

4 years ago

Wright in point-slope form, slope-intercept form and in standard form an equation that passes through (-1, 2) with slope 4

SOVA2 [1]

Answer:

$\textsf{Point-slope form}: \quad \sf y-2=4(x+1)$

$\textsf{Slope-intercept form}: \quad \sf y=4x+6$

$\textsf{Standard form}: \quad \sf 4x-y=-6$

Step-by-step explanation:

Given information:

Slope = 4
Point on line = (-1, 2)

Point-slope form of linear equation:

$\sf y-y_1=m(x-x_1)$

(where m is the slope and (x₁, y₁) is a point on the line)

Substitute the given slope and point into the formula:

$\implies \sf y-2=4(x-(-1))$

$\implies \sf y-2=4(x+1)$

Slope-intercept form of a linear equation:

$\sf y=mx+b$

(where m is the slope and b is the y-intercept)

Substitute the given slope and point into the formula and solve for b:

$\implies \sf 2=4(-1)+b$

$\implies \sf b=6$

Therefore:

$\sf y=4x+6$

Standard form of a linear equation:

$\sf Ax+By=C$

(where A, B and C are constants and A must be positive)

Rearrange the found slope-intercept form of the equation into standard form:

$\implies \sf y=4x+6$

$\implies \sf 4x-y+6=0$

$\implies \sf 4x-y=-6$

Learn more about linear equations here:

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8 0

2 years ago

Read 2 more answers

Parallel, PerpendicularOr NeitherY = 3x + 16x - 2y = 10​

Parallel, PerpendicularOr NeitherY = 3x + 16x - 2y = 10