Answer:
2y² -4y +5
Step-by-step explanation:
First you need to find the sum of y²+5y-1 and 3y²-2y+4
(y²+5y-1) + (3y²-2y+4) => y²+3y²+5y-2y-1+4
=4y²+3y+3
Next is to subtract 2y²+7y-2 from the sum calculated above in order to find the algebraic expression asked in the exercise
4y²+3y+3 -(2y²+7y-2) => 4y²-2y²+3y-7y+3+2
=2y² -4y +5
Therefore, the algebraic expression asked must be 2y² -4y +5
Answer:
y=12.5h+3.8 h
=
0.08
y
−
0.304
Step-by-step explanation:
I think that is the answer
Once she completes a wall, Sabrina notices that the number of squares along each side of the wall is equal to the number of square centimeters in each tile’s area. Write an equation for the number of squares on the wall, SW, in terms of c. Then, solve for the number of squares on the wall
g. Write an equation for the area of the wall, Aw. Then solve for the area of the wall.
E=mc2 is one of the most recognizable equations in the world. In this task, you’ll attempt to understand it better. Let’s start with what the letters mean. The letter E stands for energy, the letter m stands for mass, and the letter c stands for the speed of light. The meaning of this equation is that you can completely convert mass into energy.
a. Rewrite the equation to solve for the speed of light, c. Use rational exponents instead of roots.
b. Using the properties of exponents, apply the rational exponent to the numerator and the denominator, and then rationalize the denominator.
c. Rewrite this equation without writing it as a fraction. (Fractional exponents are OK, though.)
d. Using whichever equation you prefer (part a, b, or c), find the speed of light in meters per second if a mass of 3 kilograms converts to 2.7 × 10^17 joules (J = kg·m^2/s^2
