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HACTEHA [7]
3 years ago
6

If the legs of a right angle are 3 feet and 4 feet, the length of the hypotenuse is how many feet

Mathematics
1 answer:
damaskus [11]3 years ago
6 0
Hi there!

• Base, b = 3 ft
• Perpendicular, p = 4 ft.

According t' Pythagoras theorem :-

h = \sqrt {b^2 + p^2}

h = \sqrt {3^2 + 4^2}

h = \sqrt {9 + 16}

h = \sqrt {25} = 5 ft.

Hence,
Th required length of Hypotenuse, h = 5 ft.

~ Hope it helps!
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Rewrite the equation by completing the square. x^{2}+16x+64 = 0
Ostrovityanka [42]

Answer:

(x+8)²

Step-by-step explanation:

x² + 16x + 64 = (x+8)²

(x+8)² = (x+8)(x+8) = x*x + x*8 + 8*x + 8*8 = x² + 8x + 8x + 64

         = x² + 16x + 64

8 0
3 years ago
1.Show that the statement p: “If x is a real number such that x3 + 4x = 0, then x is 0” is true by
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8 0
3 years ago
What is value of x? Please help! Will reward
vazorg [7]

x = 50

The angles shown are vertically opposite and thus equal

so 3x - 30 = 2(x + 10)

3x - 30 = 2x +20

subtract 2x from both sides

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x - 30 = 20

add 30 to both sides

x = 20 + 30 = 50


5 0
3 years ago
Read 2 more answers
Plz will mark as brainliest ​
Alenkasestr [34]

Answer:

30

Step-by-step explanation:

1/2 x (a+b) x h = area

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1/2 (40 + x )= 1750/50

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1/2 x = 35 - 20

x = 15 x 2

= 30

I hope this is right :)

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3 years ago
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