<span>For a parallelogram to be proven to be a rectange, the opposide sides must be parallel and the two adjacent sides must be perpendicular.
For two parallel sides, the slope of the two sides is equal.
Thus, for the parallelogram to be a rectangle, AB is parallel to CD.
The slope of AB = (y2 - y1)/(x2 - x1) while the slope of CD = (y4 - y3)/(x4 - x3)
Also, BC is perpedicular to CD.
For two perpendicular sides, the product of the slopes is -1.
The slope of BC is given by (y3 - y2)/(x3 - x2).
Therefore, for the parallelogram to be a rectangle.
(y2 - y1)/(x2 - x1) = (y4 - y3)/(x4 - x3) and (y4 - y3)/(x4 - x3) x (y3 - y2)/(x3 - x2) = -1.
The third option is the correct answer.</span>
Answer:
£13800
Step-by-step explanation:
1150*12=£13800
Since sides kl and kj are congruent that means that angles klj and kjl are congruent. if angle klj is 58 then that means kjl is also 58. so you take the total number of degrees in a triangle (180) and subtract 58 and 58 (116) which leaves you with 64 ( the degree measure of lkj)