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2 years ago

Find the area of the triangle that divides the parallelogram in half

Mathematics

1 answer:

Gennadij [26K]2 years ago

5 0

Could you please provide a picture so we can answer it better?

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HHHHHEEEEEELLLLLPPPPP Parker drove a total distance of 4 and 1 over 2 miles during the months of June and July. If Parker only d

goldenfox [79]

Answer:

use cymath for answer

Step-by-step explanation:

it will explain better

8 0

2 years ago

Read 2 more answers

Can someone help me in #66

VladimirAG [237]

$\bf log_{{ a}}(xy)\implies log_{{ a}}(x)+log_{{ a}}(y)
\\ \quad \\
% Logarithm of rationals
log_{{ a}}\left( \frac{x}{y}\right)\implies log_{{ a}}(x)-log_{{ a}}(y)
\\ \quad \\
% Logarithm of exponentials
log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)\\\\
-------------------------------\\\\
$

$\bf log_4\left( \cfrac{\sqrt{x^5y^7}}{zw^4} \right)\implies log_4(\sqrt{x^5y^7})-log_4(zw^4)
\\\\\\
log_4\left[(x^5y^7)^{^\frac{1}{2}}\right]-log_4(zw^4)\implies 
\cfrac{1}{2}log_4\left[(x^5y^7)\right]-log_4(zw^4)
\\\\\\
\cfrac{1}{2}\left[ log_4(x^5)+log_4(y^7) \right] -[log_4(z)+log_4(w^4)]
\\\\\\
\cfrac{1}{2}log_4(x^5)+\cfrac{1}{2}log_4(y^7)-[log_4(z)+log_4(w^4)]$

$\bf \cfrac{1}{2}\cdot 5log_4(x)+\cfrac{1}{2}\cdot 7log_4(y)-log_4(z)-4log_4(w)
\\\\\\
\cfrac{5}{2}log_4(x)+\cfrac{7}{2}log_4(y)-log_4(z)-4log_4(w)$

6 0

3 years ago

You work two jobs. You earn $9.45 per hour as a salesperson and $11.34 per hour stocking shelves. Your combined earnings this mo

konstantin123 [22]

Answer:

11.34x + 9.45y = 141.75

y = (141.75 - 11.34x)/9.45

y = -1.2x + 15

Draw a straight line only in the first quadrant connecting these points:

(0,15)

(12.5,0)

6 0

3 years ago

PLEASE HELP ME!

kotegsom [21]

Answer:

Bottom left graph

Step-by-step explanation:

We have to use what is called the zero-interval test [test point] in order to figure out which portion of the graph these inequalities share:

−2x + y ≤ 4 >> Original Standard Equation

+ 2x + 2x

_________

y ≤ 2x + 4 >> Slope-Intercept Equation

−2[0] + 0 ≤ 4

0 ≤ 4 ☑ [We shade the part of the graph that CONTAINS THE ORIGIN, which is the right side.]

$\displaystyle y > x + 2 \\ \\ 0 ≯ 2$ [We shade the part of the graph that does not contain the origin, which is the left side.]

So, now that we got that all cleared up, we can tell that the graphs share a region in between each other and that they both have POSITIVE RATE OF CHANGES [SLOPES], therefore the bottom left graph matches what we want.

** By the way, you meant $\displaystyle y > x + 2$ because this inequality in each graph is a dashed line. It is ALWAYS significant that you be very cautious about which inequalities to choose when graphing. Inequalities can really trip some people up, so once again, please be very careful.

I am joyous to assist you anytime.

7 0

3 years ago

I need help 9th grade math

alexira [117]

hope helps with the first the rest i cant read its not clear.

3 0

2 years ago