Answer:
139,999
Step-by-step explanation:
If the digit sum of n is divisible by 5, the digit sum of n+1 can't physically be divisble by 5, unless we utilise 9's at the end, this way whenever we take a number in the tens (i.e. 19), the n+1 will be 1 off being divisble, so if we take a number in the hundreds, (109, remember it must have as many 9's at the end as possible) the n+1 will be 2 off being divisble, so continuing this into the thousands being three, tenthousands being 4, the hundred thousands will be 5 off (or also divisble by 5). So if we stick a 1 in the beginning (for the lowest value), and fill the last digits with 9's, we by process of elimination realise that the tenthousands digit must be 3 such that the digit sum is divisible by 5, therefore we get 139,999
You first switch f(x) with x in this equation
<span>x=<span>1<span>9f(x)−2</span></span></span>
Then you solve for f(x).
<span>9f(x)−2=<span>1x</span></span>
<span>9f(x)=<span>1x</span>+2</span>
<span>f(x)=<span>1<span>/9x</span></span>+<span>2/9</span></span>
Then you simply repalace f(x) with f^-1(x)
It will look like this
<span><span>f−</span>1(x)=<span>1<span>/9x</span></span>+<span>2/<span>9
Hope i could help
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Answer:
ok, so 46 times 4 is 184.
Step-by-step explanation:
46
x 4
-------
184
So 6 times 4 is 24 and then you carry over the 2. 4 times 4 is 16. You add 2 to 16 and you get 18. So the total would be 184.
It's kinda hard to explain over brainly
−12√2
(mark brainliest if correct plss)