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MrMuchimi
3 years ago
15

There are 16 entrees available at a restaurant. From these, Archie is to choose 6 for his party. How many groups of 6 entrees ca

n he choose, assuming that the order of the entrees chosen does not matter ?
Mathematics
1 answer:
goblinko [34]3 years ago
4 0

Answer: 8008

Step-by-step explanation:

Total entrees = 16

Number of entrees to choose = 6

Since order does not matter , so we combinations .

Number of combinations to choose r things out of n = C(n,r)=\dfrac{n!}{r!(n-r)!}

Then, total ways to choose 6 entrees = C(16,6)=\dfrac{16!}{6!10!}

=\dfrac{16\times15\times14\times13\times12\times11\times10!}{(720)10!}\\\\= 8008

Hence, the required number of ways= 8008

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