Answer:
Amount of money invested is $2,000 and $4,000
Explanation:
In this question, we are asked to calculate how much was invested in two different accounts given the amount of money invested in both accounts.
Let the amount of money invested in both accounts be a and b respectively.
Mathematically;
A + B = 6000 ......I
Now we use the formula for simple interest to check the amount that is supposed to be made on Both accounts if he end of a year.
Formula for simple interest is I = PRT/100
Let’s apply this to what is on ground:
5*1* a/100 = 5a/100
Second is
9*b*1/100 = 9b/100
That is 5a + 9b = 38,000. ........ii
Solving Both simultaneously as follows:
Let A = 6000-b from 1
Substitute this into 2
5(6000-b) + 9b = 38,000
30,000 -5b + 9b = 38,000
4b = 8,000
b =$2000
This means a would be 6000 - 2,000 = $4000
