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3 years ago

Answer fast please !!

Mathematics

1 answer:

dusya [7]3 years ago

6 0

Your answer is the third option.

I hope this helps you!
xo, Leafling

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Use the distributive property to write the following expressions in expanded form.

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

a. 4x+4y

b. 8a+24b

c. 6x+33y

d. 63a+54b

e. 3ac+bc

f. 2xy+11yz

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3 years ago

Martina read that approximately 10% of all people are left-handed. She wants to design a simulation to approximate the probabili

marta [7]

Answer:

Step-by-step explanation:

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3 years ago

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Can someone help me with the question in the image. if correct i will mark as brainliest

Alex777 [14]

Answer:

$Multiply~the~length~of~the~leg~by~\sqrt{2}~to~arrive~at~the~length$ $of~the~hypotenuse = 6.$

Step-by-step explanation:

$To~find~the~length~of~the~ hypotenuse,~we~multiply~the~length~of~the~leg$ $by~\sqrt{2}:$

$3\sqrt{2} *\sqrt{2}=3*2=6$

$So~your~answer~to~this~question~is~option"b"$

$Hope~this~helps!$

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4 years ago

Tony wants to calculate his average quiz score. The formula gives Tony’s average score A for a total of T points on n quizzes. T

Gnoma [55]

In calculating the average score, add the scores of each person and then divide it by the number of scores present. In this problem, Tony has forty seven points for five different quizzes. You are required to calculate for the average score of Tony. The formula is A = T/n, where A is the average score, T is the score, and n is the number of quizzes.

A = T/n
A = 47/5
<u>A = 9.4</u> <span>
Therefore, Tony has an average of 9.4 points in five different quizzes. </span>

6 0

3 years ago

Lim x--> 0 (e^x(sinx)(tax))/x^2

Tom [10]

Make use of the known limit,

$\displaystyle\lim_{x\to0}\frac{\sin x}x=1$

We have

$\displaystyle\lim_{x\to0}\frac{e^x\sin x\tan x}{x^2}=\left(\lim_{x\to0}\frac{e^x}{\cos x}\right)\left(\lim_{x\to0}\frac{\sin^2x}{x^2}\right)$

since $\tan x=\dfrac{\sin x}{\cos x}$ , and the limit of a product is the same as the product of limits.

$\dfrac{e^x}{\cos x}$ is continuous at $x=0$ , and $\dfrac{e^0}{\cos 0}=1$ . The remaining limit is also 1, since

$\displaystyle\lim_{x\to0}\frac{\sin^2x}{x^2}=\left(\lim_{x\to0}\frac{\sin x}x\right)^2=1^2=1$

so the overall limit is 1.

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3 years ago