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Ray Of Light [21]
3 years ago
11

PLZ HELP ME WITH THIS, I'VE BEEN STUCK ON THIS FOR A WHILE.

Mathematics
1 answer:
Serga [27]3 years ago
4 0

Answer:

it is blink

Step-by-step explanation:

vgftr

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Which is a common denominator for 3/7 and 1/3? 21, 10, 9, 7
kykrilka [37]

Answer:

a common denominator for 3/7 and 1/3 is 21

3 0
3 years ago
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How would you substitute 2x+3y=12 and 4x=10+y
Helen [10]

Answer:

<h2>x = 3, y = 2</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}2x+3y=12\\4x=10+y&\text{subtract 10 from both sides}\end{array}\right\\\\\left\{\begin{array}{ccc}2x+3y=12&(1)\\4x-10=y&(2)\end{array}\right\\\\\text{Substitute (2) to (1):}\\\\2x+3(4x-10)=12\qquad\text{use the distributive property}\\2x+(3)(4x)+(3)(-10)=12\\2x+12x-30=12\qquad\text{add 30 to both sides}\\14x-30+30=12+30\\14x=42\qquad\text{divide both sides by 14}\\\\\dfrac{14x}{14}=\dfrac{42}{14}\\\\x=3

\text{Put it ot (2):}\\\\y=4(3)-10\\y=12-10\\y=2

3 0
3 years ago
In a 30°-60°-90° triangle, the length of the hypotenuse is 30. Find the length of the longer leg.
Assoli18 [71]
<span>In a 30-60-90  triangle the side opposite the 30 degree angle is half the length of the hypotenuse. 
The shorter leg is </span>the side opposite the 30 degree angle, therefore
the shorter leg = 30/2 = 15

<span>By the Pythagorean theorem
</span><span>the longer leg = </span>√(30² - 15²) = √(900-225) = √675 = 15√3 ≈ 25.98 units
6 0
4 years ago
A quality assurance engineer randomly checks manufactured parts to ensure that they are within 0.002 mm of the desired specifica
Neko [114]
|x - 3| ≤ 0.002 your answer should be A
4 0
3 years ago
Read 2 more answers
1. Determine the variables in the figure below.<br> 20<br> 50
Marina CMI [18]

Answer:

r=8

t=4√29

Step-by-step explanation:

By the altitude leg theorem:

{20}^{2}  = 50r

This implies that:

r =  \frac{20 \times 20}{50}

We simplify to obtain:

r = 4 \times 2 = 8

By the Pythagoras theorem:

{t}^{2}  =  {20}^{2}  +  {8}^{2}

{t}^{2}  = 400 + 64

{t}^{2}  = 464

t =  \sqrt{464}

t = 4 \sqrt{29}

7 0
3 years ago
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