Help due asap show workings please

Mathematics

1 answer:

IceJOKER [234]2 years ago

3 0

The answer is 45. 180-90=90. 90 divided by 2 is 45

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Simplify the expression.

Marizza181 [45]

$\bf \textit{Cofunction Identities}
\\ \quad \\
sin\left(\frac{\pi}{2}-{{ \theta}}\right)=cos({{ \theta}})\qquad 
\boxed{cos\left(\frac{\pi}{2}-{{ \theta}}\right)=sin({{ \theta}})}
\\ \quad \\ \quad \\
tan\left(\frac{\pi}{2}-{{ \theta}}\right)=cot({{ \theta}})\qquad 
cot\left(\frac{\pi}{2}-{{ \theta}}\right)=tan({{ \theta}})
\\ \quad \\ \quad \\
sec\left(\frac{\pi}{2}-{{ \theta}}\right)=csc({{ \theta}})\qquad 
csc\left(\frac{\pi}{2}-{{ \theta}}\right)=sec({{ \theta}})$

$\bf \\\\
-------------------------------\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta )
\\\\\\
\boxed{cos(\theta )=\sqrt{1-sin^2(\theta )}}$

$\bf \\\\
-------------------------------\\\\
\cfrac{cos^2\left(\frac{\pi }{2}-x \right)}{\sqrt{1-sin^2(x)}}\implies \cfrac{\left[ cos\left(\frac{\pi }{2}-x \right)\right]^2}{cos(x)}\implies \cfrac{[sin(x)]^2}{cos(x)}\implies \cfrac{sin(x)sin(x)}{cos(x)}
\\\\\\
sin(x)\cdot \cfrac{sin(x)}{cos(x)}\implies sin(x)tan(x)$

6 0

3 years ago

Oleg and Anya drew these models to help them find the difference of 3/4 and 1/2.

Nikitich [7]

Answer:

Step-by-step explanation:

Oleg is correct because the least common denominator of both is 4, so each must have 4 peices

3 0

2 years ago

A student used four different tape measures to estimate the length of a meterstick manufactured to he exactly 1 meter. Which mea

Ksju [112]

Out of the four options,
A. 99 cm B. 105.98 cm C. 90 cm D. 104.5 cm,

option A is the correct answer.

Because 1 m = 100 cm and this is the nearest approximation. Thus, theA student used A tape measures to estimate the length of a meterstick manufactured to he exactly 1 meter.

6 0

3 years ago

Help for points and Ill give brainliest to correct!

Svetradugi [14.3K]

Answer:

D. 3 1/4

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Solve for a . 5 a - 2 = 23 a = ?

Margaret [11]