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vfiekz [6]
3 years ago
15

Which equation is equivalent to 1 5/6 - 2/6 = 1 3/6

Mathematics
1 answer:
Bingel [31]3 years ago
7 0
11/6-1/3 = 9/6 should be equivalent
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Formula for area the area of a triangle
nordsb [41]
I think A=12bh I hope it’s right
4 0
3 years ago
2x / 2x is equals to?​
Bond [772]
It’s equal to 1

2x divide by 2x = 1
— —
2x divide by 2x 1

which equals to 1
5 0
3 years ago
Y=x3 is that a function?
kotykmax [81]

Answer:

yes

Step-by-step explanation:

y(x) is even or odd according as y(−x)=±y(x) . Here, #y(-x)=-(-x)^3=-(-x^3)=x^3=-y(x). So, y is an odd function of x.

5 0
2 years ago
Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

7 0
2 years ago
Identify the recursive formula for the sequence given by the explicit formula An) = 20
UNO [17]

Answer: f(n) = {f(1)=-4

{f(n) = f(n-1) / 20 if n > 1

Or Answer B.

Step-by-step explanation:

8 0
3 years ago
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