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OLga [1]
3 years ago
12

1. The temperature of a body rises from -6°c to 5°c. By how much degrees does it rises? ​

Mathematics
1 answer:
babunello [35]3 years ago
3 0
It rises 11 degrees

Step by step explanation
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Find the zeroes of the polynomial function f(x)=x^4-5x^3+11x^2-25x+30.
katen-ka-za [31]

Step-by-step explanation:

x⁴ − 5x³ + 11x² − 25x + 30

x⁴ − 5x³ + 6x² + 5x² − 25x + 30

x² (x² − 5x + 6) + 5 (x² − 5x + 6)

(x² + 5) (x² − 5x + 6)

(x² + 5) (x − 2) (x −3)

The zeros are 2, 3, and ±√5i.

7 0
4 years ago
-x-2y-4z=-6<br> X-5y-2z=-2<br> 2x-3y+2z=2
Svetlanka [38]

Answer:

\sqrt{2} or (1/2)

Step-by-step explanation:

7 0
4 years ago
Write an equation in two variables in the standard form that can be used to describe the velocity of the car at different times.
ira [324]
Velocity of the car is equal to the distance travelled by the time spent.

If V= velocity, d = distance & time = t, then


the equation becomes V=d/t
3 0
3 years ago
The floor of the school art closet is being tiled. The closet is shaped like a parallelogram. The parallelogram has a base of 17
ololo11 [35]

Answer:

21  packages

Step-by-step explanation:

7 0
3 years ago
Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line.? y = 2 + se
sertanlavr [38]

Answer:

The volume of the solid is: \mathbf{V = \pi [ \dfrac{8 \pi}{3} - 2\sqrt{3}]}

Step-by-step explanation:

GIven that :

y = 2 + sec \  x , -\dfrac{\pi}{3} \leq x \leq \dfrac{\pi}{3} \\ \\ y = 4\\ \\ about \  y \ = 2

This implies that the distance between the x-axis and the axis of the rotation = 2 units

The distance between the x-axis and the inner ring is r = (2+sec x) -2

Let R be the outer radius and r be the inner radius

By integration; the volume of the of the solid  can be calculated as follows:

V = \pi \int\limits^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} [(4-2)^2 - (2+ sec \ x -2)^2]dx \\ \\ \\ V = \pi \int\limits^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} [(2)^2 - (sec \ x )^2]dx \\ \\ \\ V = \pi \int\limits^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} [4 - sec^2 \ x ]dx

V = \pi [4x - tan \  x]^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}}  \\ \\ \\ V = \pi [4(\dfrac{\pi}{3}) - tan (\dfrac{\pi}{3}) - 4(-\dfrac{\pi}{3})+ tan (-\dfrac{\pi}{3})] \\ \\ \\ V = \pi [4(\dfrac{\pi}{3}) - tan (\dfrac{\pi}{3}) + 4(\dfrac{\pi}{3})- tan (\dfrac{\pi}{3})]  \\ \\ \\ V = \pi [8(\dfrac{\pi}{3})  - 2 \  tan (\dfrac{\pi}{3}) ]

\mathbf{V = \pi [ \dfrac{8 \pi}{3} - 2\sqrt{3}]}

7 0
3 years ago
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