Linear- blue graph, table 2, 2x-3y=7, y=3\x +2, y=-4
Nonlinear- y= 2x^2+ 4
Y=-2x-8+2
y=-2x-6
if x=0;Y=-6
IF y=0;x=-3
to plot the graph; plot point in -6 y-axis and -3 on the x-axis join them together then extend the line
hope u understood
I would start at 2000 because of 400/.2 is 2000 idk sorry
100 X 6 percent = 60$
60+100=160
What’s your question
Answer:
The minimum level for which the battery pack will be classified as highly sought-after class is 2.42 hours
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the minimum level for which the battery pack will be classified as highly sought-after class
At least the 100-10 = 90th percentile, which is the value of X when Z has a pvalue of 0.9. So it is X when Z = 1.28.




The minimum level for which the battery pack will be classified as highly sought-after class is 2.42 hours