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2 years ago

Describe the association in the scatter plot.

Mathematics

2 answers:

aivan3 [116]2 years ago

7 0

Answer:

it is horizontal

Step-by-step explanation:

boyakko [2]2 years ago

6 0

Answer:

I think it's horizontal

Hope this helps!!

Please give BRAINLIST!!

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Tina practiced piano for 15 hours last month and 45 hours this month A. Use multiplication to write a statement comparing the ho

KonstantinChe [14]

Answer: The answer is (a) 3 × x = y and (b) x + x + x = y.

Step-by-step explanation: Let 'x' and 'y' denote the number of hours that Tina practised last month and this month respectively.

Then, according to the given information, we have

x = 15 and y = 45.

We can write the relation between 'x' and 'y' in two forms as follows -

(a) Multiplication form : 3 × 5 = 15 implies 3 × x = y.

(b) Addition form : 15 +15 +15 = 45 implies x + x + x = y.

Thus, the answers are (3 × x = y) and (x + x + x = y).

4 0

3 years ago

Solve each equation.SHOW work plz

Studentka2010 [4]

$3 \frac{1}{2} r = 28 \\ \frac{7}{2} r = 28 \\ \frac{ \frac{7}{2} }{ \frac{7}{2} } r = \frac{28}{ \frac{7}{2} } \\ r = \frac{ \frac{56}{2} }{ \frac{7}{2} } \\ r= \frac{56}{7}$

$1 \frac{1}{2} c =6 \\ \frac{3}{2} c= \frac{12}{2} \\ \frac{ \frac{3}{2} }{ \frac{3}{2} } c= \frac{ \frac{12}{2} }{ \frac{3}{2} } \\ c= \frac{ \frac{12}{2} }{ \frac{3}{2} } = \frac{12}{3} =4 \\ c=4$

7 0

3 years ago

Prove diagonals of a rhombus are perpendicular

Lisa [10]

Answer:

A rhombus is a parallelogram with four congruent sides.

So, all sides of rhombus ABCD are congruent.

i.e, $\overline{JM} \cong \overline{JK} \cong \overline{KL}\cong \overline{LM}$

Also, we know that the diagonals of a parallelogram bisect each other.

Since a rhombus is a parallelogram.

By property of rhombus , if point N is the intersection of the diagonals as shown in the figure, then

$\overline{MN} \cong \overline{NK}$ .....[1]

$\overline{JN} \cong \overline{NL}$

In ΔJNM and ΔJNK

$\overline{MN} \cong \overline{NK}$ [side] [by (1)]

$\overline{JM} \cong \overline{JK}$ [side] [Given]

By reflexive property states that a segment is congruent to itself:

$\overline{JN} \cong \overline{JN}$ [Side] [Reflexive Property]

SSS(Side-Side-Side) postulates states that if three sides of one triangle are congruent to three sides of another triangle, then the two triangles are congruent.

then by SSS congruence,

$\triangle JNM \cong \triangle JNK$