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sineoko [7]
2 years ago
15

Math question down below

Mathematics
2 answers:
klio [65]2 years ago
7 0
The dog with the weight of 110lbs is the outlier in the equation--since the other dogs only range from 20 to 35 lbs.
Solnce55 [7]2 years ago
6 0
The dog with the weight of 110lbs is the outlier in the equation--since the other dogs are in the range 20 to 35 lbs.
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I WILL GIVE YOU BRAINLIEST!!!!!
zlopas [31]

Answer:

y=x

Step-by-step explanation:

The graph is a line

The only function that is a line is

y=x

7 0
2 years ago
True or false : There are more cups in 5 gallons than in 22 quarts ?
OleMash [197]
FALSE, there are 80 cups in 5 gallons and 88 cups in 22 quarts
6 0
3 years ago
Read 2 more answers
Simplify the expression of 3 <br> 162x^5y8/6x^2y^2
Blababa [14]

Answer:

Step-by-step explanation:

6 0
2 years ago
Find the vertical and horizontal asymptote if they exist
tresset_1 [31]

Hello!

Vertical asymptotes are determined by setting the denominator of a rational function to zero and then by solving for x.

Horizontal asymptotes are determined by:

1. If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

2. If the degree of the numerator = degree of denominator, then y = leading coefficient of numerator / leading coefficient of denominator is the horizontal asymptote.

3. If degree of numerator > degree of denominator, then there is an oblique asymptote, but no horizontal asymptote.

To find the vertical asymptote:

2x² - 10 = 0

2(x² - 5) = 0

(x - √5)(x + √5) = 0

x = √5 and x = -√5

Graphing the equation, we realize that x = -√5 is not a vertical asymptote, so therefore, the only vertical asymptote is x = √5.

To find the horizontal asymptote:

If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

Therefore, the horizontal asymptote of this function is y = 0.

Short answer: Vertical asymptote: x = √5 and horizontal asymptote: y = 0

7 0
2 years ago
Suppose , varies jointly with g and v, and j = 2 when g = 4 and v= 3.
kap26 [50]

Answer:

j = 44/3

Step-by-step explanation:

j varies jointly as g and v. This can be represented mathematically as:

j \alpha gv\\j = kgv.............(1)

Where k is a constant of proportionality

j = 2 when g = 4 and v = 3

Substitute these values into equation (1)

2 = k * 4 * 3

2 = 12 k

k = 1/6

when g = 8 and v = 11:

j = (1/6) * 8 * 11

j = 44/3

7 0
3 years ago
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