PLEASE HELP!!! ILL GIVE BRANLIEST *EXTRA POINTS* dont skip :((

What is the factored dorm of 1256x to the sixth power minus 8

katovenus [111]

Answer:

8(157x^6 - 1)

Step-by-step explanation:

1256x^6 - 8

Start by factoring out a common factor. 1256 and 8 are both divisible by 8.

1256x^6 - 8 = 8(157x^6 - 1)

157 is prime, so 157x^6 - 1 is not factorable.

Answer: 8(157x^6 - 1)

3 0

3 years ago

Find the equation of the line passing through (1,4) and (-2,-1).

wel

Answer:

y=5/3x+7/3

Step-by-step explanation:

Here are the points: (1,4) and (-2, -1)

let's first find the slope, which is with the equation m=(y2-y1)/(x2-x1) (m is the slope)

label the points:

x1=1

y1=4

x2=-2

y2=-1

now subsitute into the equation

m=(-1-4)/(-2-1)

m=-5/-3

m=5/3

the slope of the line 5/3

Here's the equation so far:

y=5/3x+b (b is a place holder)

we can substitute either one of the points into the equation so far to find b, because the line will pass through both of them>

let's use (1,4) as an example

4=5/3(1)+b

4=5/3+b

subtract 5/3 from both sides

7/3=b

Now, put it all together:

y=5/3x+7/3

Hope this helps!

8 0

3 years ago

Emma Weber purchased a bedroom set with an installment loan that has an APR of 12%. The bedroom set sells for $2,650. The store

ipn [44]

Answer:

$520.28

Step-by-step explanation:

The finance charge is the amount that Emma will pay in order to cover the processing costs of the bedroom set. In this case it would be $520.28. You have first find the down payment cost ($384) and then find how much she needs to pay each month to cover the rest of the cost ($66.34) and multiply it by the 42 months to get $2786.28. Add the down payment onto that and subtract the original cost and you will get your finance charge of $520.28. Hope this helps!

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6 0

3 years ago

A newspaper poll asked respondents if they trusted "eco friendly" labels on cleaning products. Out of 1000 adults surveyed, 498

Paul [167]

Answer:

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of respondents that trust these labels is not significanlty less than 0.5 or 50%.

Step-by-step explanation:

1) Data given and notation

n=1000 represent the random sample taken

X=498 represent the adults that trust these labels

$\hat p=\frac{498}{1000}=0.498$ estimated proportion of respondents that trust these labels

$p_o=0.5$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion of respondents that trust these labels is at least 50%:

Null hypothesis: $p\geq 0.5$

Alternative hypothesis: $p < 0.5$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.498 -0.5}{\sqrt{\frac{0.5(1-0.5)}{1000}}}=-0.126$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level is not provided but we can assume it as $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z$

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of respondents that trust these labels is not significanlty less than 0.5 or 50%.

7 0

4 years ago

Hello, id like to order3 halves of a cupcake for my family plus some extra for my 2 friends.

Sholpan [36]

Answer:

They'll each want a quarter of a cupcake.

Step-by-step explanation:

8 0

2 years ago