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3 years ago

What is two fifths the cube of a number?

Mathematics

2 answers:

nasty-shy [4]3 years ago

8 0

2x^3/5 hopefully that made sense, if it didn't im sorry!!!

ohaa [14]3 years ago

7 0

You are basically multiplying a fraction by another fraction. In this case, (2/5) * (x³/1). The resulting equation is...... 2x³/5

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Need alot of help please!!!

kirza4 [7]

A=x
B= 2x
C=3x
If you add them up =
6x =180
÷6 both sides
x=30
A=30
B=60
C=90
one angle is 90 degrees so the triangle is classified as a right triangle

8 0

3 years ago

Read 2 more answers

Z varies jointly as x and y. z=60 when x=5 and y=6. find z when x = 7 and y=3

Aneli [31]

Answer:

z = 42

Step-by-step explanation:

The question can be answered in 2 steps as follows:

Step 1: Calculation of the constant of the variation

The equation for the joint variation can be given as follows:

z = cxy ................... (1)

Where;

z = 60

c = constant = ?

x = 5

y = 6

Substituting the values into equation (1) and solve c, we have:

60 = c * 5 * 6

60 = c * 30

c = 60 / 30

c = 2

Step 2: find z when x = 7 and y = 3

Since from Step 1 c = 2, we now use equation (1) and substitute the values into it to find z as follows:

z = 2 * 7 * 3

z = 42

4 0

2 years ago

What is 332.6 to two significant figures

MA_775_DIABLO [31]

$332.6=3.3*(10^{2})$

7 0

2 years ago

12 midnight ....... tell me

docker41 [41]

Answer:

I am not getting your question .

5 0

2 years ago

Read 2 more answers

My friend sets out walking at a speed of $3$ miles per hour. I set out behind her $5$ minutes later at $4$ miles per hour. When

r-ruslan [8.4K]

Answer: The answer is 0.25 miles.

Step-by-step explanation: Given that my friend started walking at a speed of 3 miles per hour and I started 5 minutes after him at a speed of 4 miles per hour. We need to find the number of miles my friend travelled when I started walking.

Since I started 5 minutes after than my friend, so we are to find the distance travelled by my friend in 5 minutes.

In 1 hour, i.e., 60 minutes, distance travelled by my friend = 3 miles.

In 1 minute, distance travelled by my friend is

$\dfrac{3}{60}=\dfrac{1}{20}~\textup{miles}.$

Therefore, distance travelled by my friend in 5 minutes will be

$\dfrac{1}{20}\times 5=\dfrac{1}{4}=0.25~\textup{miles}.$

Thus, the answer is 0.25 miles.

3 0

2 years ago

Read 2 more answers