$\text{The zeros:}\\\\x^3-x^2+9x-9=0\\\\x^2(x-1)+9(x-1)=0\\\\(x-1)(x^2+9)=0\iff x-1=0\ \vee\ x^2+9=0\\\\x-1=0\qquad\text{add 1 to both sides}\\x-1+1=0+1\\\boxed{x=1}\\\\x^2+9=0\qquad\text{subtract 9 from both sides}\\x^2=-9$

8 0

3 years ago

Which best explains whether a triangle with side lengths 2 in., 5 in., and 4 in. is an acute triangle?

Leviafan [203]

Answer:

The triangle is not acute because 2² + 4² < 5².

Step-by-step explanation:

4 0

2 years ago

Find the Slope of lines passing through the points: (4,5) and (6,7)

kupik [55]

the answer is 0.6 you gotta divide and multiply

4 0

2 years ago

What is the value of x in the equation in ( x + 6)- in (2x-1) =1

ki77a [65]

Answer:

x= -5

Step-by-step explanation:

5 0

3 years ago