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Gwar [14]
3 years ago
8

In what quadrant would the ordered pair (-5, 4) be located? I II III IV

Mathematics
1 answer:
statuscvo [17]3 years ago
7 0
Ok, so
 Quadrants are found on coordinate planes. So the first number tells you to go on the X axis. It goes this way ---------
you look on the left side side of the origin (zero) and go to -5
since the second umber will be found on the Y axis, and is positive, go up to 4.
That is how you find your point.  The qudrants are counted like this.
2 1 
3 4
The answer is Quadrant 2
Hope it helped☺
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cyclic quadrilateral

This statement is always true:

Opposite angles add up to 180°

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1 year ago
What is the solution of the equation?
elena-s [515]

Answer:

Step-by-step explanation:

its c=5

6y+18+3=51

6y+21=51

6y=51-21

6y=30

y=5

4 0
3 years ago
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Find the quotient of 3/5 and 2/3
faltersainse [42]

Answer:

9/10

Step-by-step explanation:

Dividing by a fraction is the same as multiplying by that fraction's reciprocal (basically the fraction flipped).

\frac{3}{5} ÷ \frac{2}{3} = \frac{3}{5} *\frac{3}{2} =\frac{3*3}{5*2} =\frac{9}{10}

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Solve the following initial-value problem, showing all work, including a clear general solution as well as the particular soluti
Vikki [24]

Answer:

General Solution is y=x^{3}+cx^{2} and the particular solution is  y=x^{3}-\frac{1}{2}x^{2}

Step-by-step explanation:

x\frac{\mathrm{dy} }{\mathrm{d} x}=x^{3}+3y\\\\Rearranging \\\\x\frac{\mathrm{dy} }{\mathrm{d} x}-3y=x^{3}\\\\\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{3y}{x}=x^{2}

This is a linear diffrential equation of type

\frac{\mathrm{d} y}{\mathrm{d} x}+p(x)y=q(x)..................(i)

here p(x)=\frac{-2}{x}

q(x)=x^{2}

The solution of equation i is given by

y\times e^{\int p(x)dx}=\int  e^{\int p(x)dx}\times q(x)dx

we have e^{\int p(x)dx}=e^{\int \frac{-2}{x}dx}\\\\e^{\int \frac{-2}{x}dx}=e^{-2ln(x)}\\\\=e^{ln(x^{-2})}\\\\=\frac{1}{x^{2} } \\\\\because e^{ln(f(x))}=f(x)]\\\\Thus\\\\e^{\int p(x)dx}=\frac{1}{x^{2}}

Thus the solution becomes

\tfrac{y}{x^{2}}=\int \frac{1}{x^{2}}\times x^{2}dx\\\\\tfrac{y}{x^{2}}=\int 1dx\\\\\tfrac{y}{x^{2}}=x+cy=x^{3}+cx^{2

This is the general solution now to find the particular solution we put value of x=2 for which y=6

we have 6=8+4c

Thus solving for c we get c = -1/2

Thus particular solution becomes

y=x^{3}-\frac{1}{2}x^{2}

5 0
4 years ago
the temperature is already at 40 degrees it rises 4.5 degrees per minute how long will it take to get to 76 degrees​
Andrei [34K]

Answer:

It will take 8 minutes for the temperature to reach 76°

Step-by-step explanation:

The expression for the total temperature in degrees at time t can be written as;

T=I+EM

where;

T=total temperature

I=initial temperature

E=temperature increase per minute

M=number of minutes

This can also be written as;

total temperature=initial temperature+temperature increase per minute×number of minutes

In our case;

T=76°

I=40°

E=4.5°

M=m

replacing;

76=40+(4.5×m)

4.5 m=76-40=36

(4.5 m)/4.5=36/4.5

m=8

It will take 8 minutes for the temperature to reach 76°

7 0
4 years ago
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