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Ksju [112]
3 years ago
12

I am sketching parabolas and my book is telling me that I need only two points. But I don't know how I am meant to sketch the pa

rabola accurately with only two points. Are parabolas just supposed to be drawn roughly or do we have to find all the points and then sketch it?
Mathematics
1 answer:
Sever21 [200]3 years ago
7 0

Answer:

In order to sketch a parabola, one will typically use the y-intercept, the x-intercepts, and the vertex.

Step-by-step explanation:

In order to sketch a parabola, one will typically use the given equation in standard form, y = ax^2 + bx + c, and:

  • The y-intercept – the point where the parabola crosses the vertical axis – by substituting 0 for all <em>x</em> values in the given equation and solving for <em>y</em>.
  • The x-intercepts – the points where the parabola crosses the horizontal axis – by setting the given equation equal to 0 (i.e., <em>y</em> = 0) and finding the factors (or roots).
  • The vertex – the point of symmetry where the parabola changes direction and curves up or down – by using x=\frac{-b}{2a} to find the x-coordinate then plugging that value into the given equation to find the y-coordinate.
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Answer:

A. -4

Step-by-step explanation:

Given the function f(x) = x + 3 for x ≤ -1 and 2x - c for x > -1, for the function to be continuous, the right hand limit of the function must be equal to its left hand limit.

For the left hand limit;

The function at the left hand occurs at x<-1

f-(x) = x+3

f-(-1) = -1+3

f-(-1) = 2

For the right hand limit, the function occurs at x>-1

f+(x) = 2x-c

f+(-1) = 2(-1)-c

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For the function f(x) to be continuous on the entire real line at x = -1, then

f-(-1) = f+(-1)

On equating both sides:

2 = -2-c

Add 2 to both sides

2+2 = -2-c+2

4 =-c

Multiply both sides by minus.

-(-c) = -4

c = -4

Hence the value of c so that f(x) is continuous on the entire real line is -4

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3 years ago
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Answer:

C

Step-by-step explanation:

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Step-by-step explanation:

i hope this helps :)

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