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3 years ago

8

an article when sold at a profit of 5% yields rupees 50 more than when sold at a loss of 5% what was the cost price of the artic

le

1 answer:

ziro4ka [17]3 years ago

6 0

I'm going to assume that the question should say “at a profit of 5%”.

Restate question in the form of a equation.

Let C = the cost price of the item.

C + 0.705 C = C - 0.05 C + Rs 50

0.05 C = - 0.05 C + Rs 50

0.10 C = Rs 50

C = Rs 500

The cost price of the item is Rs 500

I hope this help you

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Step-by-step explanation:

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3 years ago

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3 years ago

Find the equation of a line that contains the points (3,7) and (-6, 4). Write the equation in slope-intercept form, using

NikAS [45]

Answer:

$y=\frac{1}{3} x+6$

Step-by-step explanation:

$(3,7)(-6,4)$

Step 1. Find the slope (by using the slope-formula)

m = slope

$m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{4-7}{-6-3}$

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Step 2. Write the equation (using the slope and the points)

Here's how to do it:

Slope-intercept Formula $y=mx+b$ whrere m = slope and b = y-intercept

Plug in the slope into the Slope-intercept Formula

$y=\frac{1}{3} x+b$

Find the y-intercept (b) by using a point and substituting their x and y values

$y=\frac{1}{3} x+b$

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$7=1+b$

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Step 3. Write the equation in Slope-intercept form

$y=mx+b$

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3 0

2 years ago

you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

2 years ago