What is the absolute deviation and range of the data set 134 139 145 152 174

Please someone answer this, “what is the area of triangle ABC?”

prisoha [69]

Here's the solution,

The given triangle is an <u>equilateral triangle</u>, because it's all angles measure 60° each

now,

Area of an equilateral triangle :

=》

$\dfrac{ \sqrt{3} }{4} {a}^{2}$

where,

a = 8 ( side measure )

=》

$\dfrac{ \sqrt{3} }{4} \times 8 \times 8$

=》

$\sqrt{3} \times 16$

=》

$16 \sqrt{3} \: \: \: cm {}^{2}$

or

=》

$27.71 \: \: cm {}^{2}$

4 0

3 years ago

Fill in the blanks below.

Crank

The slope for the first one would be:
y2-y1/x2-x1, so replace those with the coordinates and you'll get:
-3-1/-7-(-7) => -4/0 so I guess the slope is zero

the slope for the second one would be:
-3-(-3)/5-(-4)=> 0/9 I think this one would be undefined.
Check to make sure, though!

4 0

3 years ago

Read 2 more answers

Can you discuss the differences and similarities between dividing with whole numbers and decimals.

goldenfox [79]

Answer:

Comparing a whole numbers and a decimals:

First let’s talk about the similarities of comparing whole numbers and decimals:

=> their place value always matters.

Now, let’s proceed to their differences

=> in comparing whole numbers, we don’t care about the value to the nearest decimal points or the value of ones. We always look at the highest value, not unless the highest values are all the same.

=> In comparing decimals, the value to the nearest decimal points or the tenths place value always matters.

5 0

3 years ago

A realtor would like to create a 95% confidence interval for the average price of a house in Franklin County, Ohio. To accomplis

VMariaS [17]

Answer:

$320128-1.96\frac{50324}{\sqrt{529}}=315839.52$

$320128+1.96\frac{50324}{\sqrt{529}}=324416.48$

So on this case the 95% confidence interval would be given by (315839.52;324416.48)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=320128$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=50324$ represent the population standard deviation

n=529 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$