Answer:

Step-by-step explanation:

We have been given that you drop a ball from a window 50 metres above the ground. The ball bounces to 50% of its previous height with each bounce. We are asked to find the total distance traveled by up and down from the time it was dropped from the window until the 25th bounce.
We will use sum of geometric sequence formula to solve our given problem.
, where,
a = First term of sequence,
r = Common ratio,
n = Number of terms.
For our given problem
,
and
.





Therefore, the ball will travel 100 meters and option B is the correct choice.
2^31
use the rule that states the product of the same base with different powers you add them
(a^n) times (a^m) = a^(n+m)
Answer:
[0,1.75]
Step-by-step explanation:
range is the y value