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Firdavs [7]
3 years ago
12

Find the greatest common factor whats 24 and 30

Mathematics
1 answer:
dem82 [27]3 years ago
4 0

Answer:

6

Step-by-step explanation:

we will calculate the prime factors( gcd) of the numbers by matching the biggest comman factor of 24 or 30

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How many extraneous solutions does the equation below have? StartFraction 9 Over n squared 1 EndFraction = StartFraction n 3 Ove
BigorU [14]

The equation has one extraneous solution which is n ≈ 2.38450287.

Given that,

The equation;

\dfrac{9}{n^2+1} =\dfrac{n+3}{4}

We have to find,

How many extraneous solutions does the equation?

According to the question,

An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.

To solve the equation cross multiplication process is applied following all the steps given below.

\rm \dfrac{9}{n^2+1} =\dfrac{n+3}{4}\\\\9 (4) = (n+3) (n^2+1)\\\\36 = n(n^2+1) + 3 (n^2+1)\\\\36 = n^3+ n + 3n^2+3\\\\n^3+ n + 3n^2+3 - 36=0\\\\n^3+ 3n^2+n -33=0\\

The roots (zeros) are the  x  values where the graph intersects the x-axis. To find the roots (zeros), replace  y

with  0  and solve for  x. The graph of the equation is attached.

n  ≈  2.38450287

Hence, The equation has one extraneous solution which is n  ≈  2.38450287

For more information refer to the link.

brainly.com/question/15070282

5 0
2 years ago
Simplify each expression. (7x+x^4+x^3)-(6x-2x^3+8x^4)
aleksandrvk [35]
the answer is x + 3x^3 - 7x^4
8 0
2 years ago
sam divided a rectangle into 8 congruent rectangles that each have a area of 5 cm2. what is the area of the rectangle before it
Vikki [24]
Congruent= the same shape and size.

area of the rectangle before it is divided=8*(area congruent rectangle)
area of the rectangle before it is dividide=8*(5 cm²)=40 cm²

Area of the rectangle before it is dividide=40 cm²
5 0
3 years ago
4 1/2 cups converted to fluid ounces
Dmitry_Shevchenko [17]

Answer:

4.5 cup to oz is 36 FLUID OUNCES

6 0
3 years ago
Solve for x. x = log44
kkurt [141]
First, set the equation in exponential form. 
x=logbY  to  b^x=Y
x=log44.  so x=x, b=10, Y=44
10^x=44  
I know that 10^1=10, 10^2=100, and 10^1.5=31.6 so x should be between 1.5 and 2.
The answer is x=1.64.  


3 0
3 years ago
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