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sertanlavr [38]

3 years ago

14

.002 is 1/10 of what

1 answer:

8_murik_8 [283]3 years ago

3 0

This uses the concept of proportions.

.002 converted to a fraction is 2/1000, or 1/500.

We set up the proportion like so:
10/100 = .002/x
Solve for x.

Cross-multiply.
10 * x = .002 * 100
10 * x = .2
x = .2 / 10
x = .02

The answer is .02

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Need help please.........thank you

crimeas [40]

A²-b²=(a-b)(a+b)
4x² - 25= (2x)²- 5² =(2x-5)(2x+5)
You do not have this choice, so the answer is D.None of the above.

6 0

2 years ago

Read 2 more answers

I WILL GIVE BRAINLIEST to who answers this question right

nydimaria [60]

Answer:

41 2/3 feet

Step-by-step explanation:

The sum of wall lengths (in feet) is ...

(12 1/4) + (10) + (12 1/4) + (10 -2 5/6)

= (12 + 10 + 12 + 8) + (1/4 + 1/4 - 5/6)

= 42 + (3/12 + 3/12 -10/12)

= 42 - 4/12 = 42 - 1/3

= 41 2/3 . . . feet

7 0

3 years ago

i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

<u>Solving the trigonometry functions</u>

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

3 0

2 years ago

Given the linear equation 2x + y = 6, perform the necessary operations to put the equation into the proper general form. Explain

Dafna11 [192]

Answer: equation equals to the 7th power of the point from the excellence of the number

Step-by-step explanation:

3 0

3 years ago

Kirk is uploading a large video file to a video sharing website. After 9 minutes, 17% of the video file has been uploaded. If th

Hatshy [7]

Answer:

53 minutes

Step-by-step explanation:

Let x be the time required for a full video upload. This would have the unit of (minutes/full upload). Since the upload rate is constant, we can write:

(0.17)*(x) = 9 minutes

This equation states that 17% of the full upload time is 9 minutes.

Solve for x:

x = (9 minutes)/(0.17)

x = 52.9 minutes or 53 minutes with 2 sig figs

8 0

2 years ago