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grin007 [14]
3 years ago
10

Marking brainliest Can someone give me an example on why animal testing is bad?

Mathematics
1 answer:
DENIUS [597]3 years ago
4 0
Wdym by animal testing? Like doing experiments on rats as an example?
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Two trapeziums are similar, thee area of one of the trapezium is 4times that of the other. Determine the ratio of the perimeter
Stolb23 [73]

Answer:

The ratio of the perimeters of the two trapezium is 2

The ratio of the corresponding sides of the two trapezium is 2

Step-by-step explanation:

The given parameters in the question are;

Two trapeziums are similar

The area of one trapezium = 4 × The area of the other trapezium

Let, A₁, and A₂ represent the area of the two trapeziums, we have

A₁ = 4 × A₂

∴ A₁/A₂ = 4

Given that ratio of areas = (Ratio of sides)²

Ratio of sides = Ratio of perimeter

∴ Ratio of areas = (Ratio of perimeter)²

Therefore, given that the ratio of the areas of the two trapeziums A₁/A₂ = 4, we have;

Ratio of areas = 4 = (Ratio of sides)²

The ratio of the corresponding sides = √4 = 2

The ratio of the corresponding sides = 2

Ratio of areas = 4 = (Ratio of perimeter)²

The ratio of the perimeter = √4 = 2

The ratio of the perimeter = 2

3 0
3 years ago
A person jogs 1/4 mile in 1/16 hour. The person's speed is ______ miles per hour.
Gemiola [76]
It would be 4 miles an hour because just adding one of its self untill the 1/16 is whole would be that 1/4 has made 4 of its self already
8 0
4 years ago
Read 2 more answers
Can someone please help me with this thank you!!
kotykmax [81]

Answer:

1. add up all of the arcs.

2x+3x+4x-8+x-12

2. all of the arcs equal 360

2x+3x+4x-8+x-12=360

3. Find x

10x-20=360, x=38

4. angle LTE is equal to half of the sum of the intercepted arcs.

.5(arc LE +GF)

5. plug in LE +GF with x

.5(76+144)

LTE=110

8 0
4 years ago
Prove the following identity ​
Deffense [45]

Answer:

sec(x)/(tan xsin(x))=cot^2 x+1 = Ture

Step-by-step explanation:

Verify the following identity:

sec(x)/(tan(x) sin(x)) = cot(x)^2 + 1

Hint: | Eliminate the denominator on the left hand side.

Multiply both sides by sin(x) tan(x):

sec(x) = ^?sin(x) tan(x) (cot(x)^2 + 1)

Hint: | Express both sides in terms of sine and cosine.

Write cotangent as cosine/sine, secant as 1/cosine and tangent as sine/cosine:

1/cos(x) = ^?sin(x)/cos(x) sin(x) ((cos(x)/sin(x))^2 + 1)

Hint: | Simplify the right hand side.

((cos(x)/sin(x))^2 + 1) sin(x) (sin(x)/cos(x)) = (((cos(x)^2)/(sin(x)^2) + 1) sin(x)^2)/(cos(x)):

1/cos(x) = ^?(sin(x)^2 (cos(x)^2/sin(x)^2 + 1))/cos(x)

Hint: | Put the fractions in cos(x)^2/sin(x)^2 + 1 over a common denominator.

Put cos(x)^2/sin(x)^2 + 1 over the common denominator sin(x)^2: cos(x)^2/sin(x)^2 + 1 = (cos(x)^2 + sin(x)^2)/sin(x)^2:

1/cos(x) = ^?sin(x)^2/cos(x) (cos(x)^2 + sin(x)^2)/sin(x)^2

Hint: | Cancel down ((cos(x)^2 + sin(x)^2) sin(x)^2)/(sin(x)^2 cos(x)).

Cancel sin(x)^2 from the numerator and denominator. ((cos(x)^2 + sin(x)^2) sin(x)^2)/(sin(x)^2 cos(x)) = (sin(x)^2 (cos(x)^2 + sin(x)^2))/(sin(x)^2 cos(x)) = (cos(x)^2 + sin(x)^2)/cos(x):

1/cos(x) = ^?(cos(x)^2 + sin(x)^2)/cos(x)

Hint: | Eliminate the denominators on both sides.

Multiply both sides by cos(x):

1 = ^?cos(x)^2 + sin(x)^2

Hint: | Use the Pythagorean identity on cos(x)^2 + sin(x)^2.

Substitute cos(x)^2 + sin(x)^2 = 1:

1 = ^?1

Hint: | Come to a conclusion.

The left hand side and right hand side are identical:

Answer: (identity has been verified)

3 0
2 years ago
Factorise x²+8x+12plz give answer ​
larisa86 [58]

Answer:

(x+6)(x+2)

Step-by-step explanation:

we have

ax²+bx+c

To factor parabolas we need to find a number that adds to b (or 8) and mulitplies to a*c (or 12)

The numbers 6 and 2 fit this criteria which means we have

(x+6)(x+2)

7 0
3 years ago
Read 2 more answers
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