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4 years ago

If f(x)= x2 + 1 and g(x) = 3x + 1, find 2f(1) + 3g(4) •45 •43 •42

Mathematics

1 answer:

Alex73 [517]4 years ago

3 0

Answer:

the answer is 43.

Step-by-step explanation:

We have functions

$f(x) = x^2+1$

$g(x)=3x+1,$

and we want to evaluate

$2f(1) + 3g(4)$

For this we first evaluate $f(1)$ and $g(4)$ separately:

$f(1)=(1)^2+1=2$

$g(4)=3(4)+1=13$

Therefore

$2f(1) + 3g(4)= 2(2)+3(13)=43$

So we have

$\boxed{2f(1) + 3g(4)=43}$

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Sanya has a piece of land which is in the shape of a rhombus. She wants her one daughter and one son to work on the land and pro

Neporo4naja [7]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

★ Sanya has a piece of land which is in the shape of a rhombus.

★ She wants her one daughter and one son to work on the land and produce different crops, for which she divides the land in two equal parts.

★ Perimeter of land = 400 m.

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${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

★ Area each of them [son and daughter] will get.

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

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So, For $\triangle$ ABD,

Here,

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• c = 160 [BD]

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Using herons formula,

$\star \tt Area \: of \: \triangle = \boxed{\bf{{ \sqrt{s(s - a)(s - b)(s - c) } }}} \star$

where

• s is the simi perimeter = 180m

• a, b and c are sides of the triangle which are 100m, 100m and 160m respectively.

Putting the values,

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180(180 - 100)(180 - 100)(180 - 160) }$

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$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{9 \times 20 \times 20 \times 80 \times 80}$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{ {3}^{2} \times {20}^{2} \times {80}^{2} }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = 3 \times 20 \times 80$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \red{ 4800 \: {m}^{2} }$

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As both the triangles have same sides

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Therefore, area each of them [son and daughter] will get = 4800 m²

${\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}$

★ Figure in attachment.

${\underline{\rule{290pt}{2pt}}}$

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