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Sergeeva-Olga [200]

2 years ago

14

Where are the black dots located at ?!!

2 answers:

Dafna1 [17]2 years ago

8 0

Answer:

-2/1 3/6 or 6/3

Step-by-step explanation:

syoydsgxhxgztisigxugxyxgisy

butalik [34]2 years ago

4 0

Answer:

(1,-2) and (6, 3)

Step-by-step explanation:

Hope this helps ^-^

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A bus travels at a constant speed. The following table shows the distance the bus travels (in kilometers) over a period of time

Olegator [25]

Answer:

315 km

Step-by-step explanation:

If the bus travels at constant speed, then the slope of the distance versus time graph can be calculated by using any two points from this table.

Let's use the points (0.5, 42) and (4.5, 378):

as we move from the first point to the second, t increases by 4 and y increases by 336. Thus, the slope of this graph is

m = rise / run = 336 km / 4 hr = 84 km/hr

then distance traveled = speed times time, or

distance traveled = (84 km/hr)t, where t is the elapsed time.

In 6 hours the bus would travel

( 84 km/hr )(6 hr) = 504 km, or approx. 315 mi

8 0

2 years ago

Read 2 more answers

Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)

ELEN [110]

Question:

Find the point (,) on the curve $y = \sqrt x$ that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

Step-by-step explanation:

$y = \sqrt x$ can be represented as: $(x,y)$

Substitute $\sqrt x$ for $y$

$(x,y) = (x,\sqrt x)$

So, next:

Calculate the distance between $(x,\sqrt x)$ and $(3,0)$

Distance is calculated as:

$d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}$

So:

$d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}$

$d = \sqrt{(x-3)^2 + (\sqrt x)^2}$

Evaluate all exponents

$d = \sqrt{x^2 - 6x +9 + x}$

Rewrite as:

$d = \sqrt{x^2 + x- 6x +9 }$

$d = \sqrt{x^2 - 5x +9 }$

Differentiate using chain rule:

Let

$u = x^2 - 5x +9$

$\frac{du}{dx} = 2x - 5$

So:

$d = \sqrt u$

$d = u^\frac{1}{2}$

$\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}$

Chain Rule:

$d' = \frac{du}{dx} * \frac{dd}{du}$

$d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}$

$d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}$

$d' = \frac{2x - 5}{2\sqrt u}$

Substitute: $u = x^2 - 5x +9$

$d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}$

Next, is to minimize (by equating d' to 0)

$\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0$

Cross Multiply

$2x - 5 = 0$

Solve for x

$2x =5$

$x = \frac{5}{2}$

Substitute $x = \frac{5}{2}$ in $y = \sqrt x$

$y = \sqrt{\frac{5}{2}}$

Split

$y = \frac{\sqrt 5}{\sqrt 2}$

Rationalize

$y = \frac{\sqrt 5}{\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$y = \frac{\sqrt {10}}{\sqrt 4}$

$y = \frac{\sqrt {10}}{2}$

Hence:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

3 0

3 years ago

Renee is participating in a fundraiser based on how far she walks around the square field at her elementary school. The field is

RUDIKE [14]

Answer:

whooooooooooooooooooooooooooooooooooooooooo

Step-by-step explanation:

5 0

3 years ago

Estimate the following difference by rounding each number to the nearest hundred.

Arte-miy333 [17]

1348.5 rounds down to 1300 because 4 is less than 5
567.21 rounds up to 600 because 6 is greater than 5
1300-600=700

8 0

3 years ago

Read 2 more answers

C=(7,-4) and D= (-8,5) CD=?

prisoha [69]

Answer:

Step-by-step explanation:

$x_{1}=7 \ ; y_{1} = -4\\\\x_{2} = -8 \ ; y_{2}=5\\\\CD = \sqrt{(-8-7)^{2}+(5-[-4])^{2}}\\\\=\sqrt{(-15)^{2}+(5+4)^{2}}\\\\=\sqrt{225+(9)^{2}}\\\\=\sqrt{225+81}\\\\=\sqrt{306}\\\\=\sqrt{3*3*2*17}\\\\=3\sqrt{34}$

Distance = $\sqrt{(x_{2}-x_{1})^{2}-(y_{2}-y_{1})^{2}}$

3 0

2 years ago