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Sergeeva-Olga [200]
3 years ago
14

Where are the black dots located at ?!!

Mathematics
2 answers:
Dafna1 [17]3 years ago
8 0

Answer:

-2/1 3/6 or 6/3

Step-by-step explanation:

syoydsgxhxgztisigxugxyxgisy

butalik [34]3 years ago
4 0

Answer:

(1,-2) and (6, 3)

Step-by-step explanation:

Hope this helps ^-^

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How do you subtract fractions with different denominators?
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Step-by-step explanation:

5 0
2 years ago
What is the difference? 5/3-1/2<br><br>A. 4<br>B. 7<br>C. 7/6<br>D. 7/0 = undefined
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The answer is:  [C]:  " ⁷/₆ " .
____________________________________
  Note:
____________________________________
   (5/3) - (1/2) = ? ;
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The LCD (lowest common denominator) of "2 and 3" is "6" ;

So we need to rewrite EACH fraction in the problem as a fraction with "6" in the denominator ;
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(1/2) = (?/6) ? ; (6÷2=3) ;  (1/2) = (1*3)/(2*3) = 3/6 ;
____________________________
Rewrite the problem:   "    (5/3) - (1/2) " ;  as:
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   10/6 - 3/6  ;
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    10/6 - 3/6 = (10 - 3) / 6 = (7/6) = 1 ⅙ .
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The answer is:  " ⁷/₆ " ;  or, write as:   " 1 ⅙ " ; which corresponds to: 
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5 0
3 years ago
Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and ro
Helga [31]

Answer:

Part 1) The shape is a trapezoid

Part 2) The perimeter is 25(4+\sqrt{2})\ units   or approximately  135.4\ units

Part 3) The area is 937.5\ units^2

Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

The shape is a trapezoid

see the attached figure

step 2

Find the perimeter

we know that

The perimeter of the trapezoid is equal to

P=AB+BC+CD+AD

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Find the distance AB

we have

A(-28,2),B(-21,-22)

substitute in the formula

d=\sqrt{(-22-2)^{2}+(-21+28)^{2}}

d=\sqrt{(-24)^{2}+(7)^{2}}

d=\sqrt{625}

d_A_B=25\ units

Find the distance BC

we have

B(-21,-22),C(27,-8)

substitute in the formula

d=\sqrt{(-8+22)^{2}+(27+21)^{2}}

d=\sqrt{(14)^{2}+(48)^{2}}

d=\sqrt{2,500}

d_B_C=50\ units

Find the distance CD

we have

C(27,-8),D(-4,9)

substitute in the formula

d=\sqrt{(9+8)^{2}+(-4-27)^{2}}

d=\sqrt{(17)^{2}+(-31)^{2}}

d=\sqrt{1,250}

d_C_D=25\sqrt{2}\ units

Find the distance AD

we have

A(-28,2),D(-4,9)

substitute in the formula

d=\sqrt{(9-2)^{2}+(-4+28)^{2}}

d=\sqrt{(7)^{2}+(24)^{2}}

d=\sqrt{625}

d_A_D=25\ units

Find the perimeter

P=25+50+25\sqrt{2}+25

P=(100+25\sqrt{2})\ units

simplify

P=25(4+\sqrt{2})\ units ----> exact value

P=135.4\ units

therefore

The perimeter is 25(4+\sqrt{2})\ units   or approximately  135.4\ units

step 3

Find the area

The area of trapezoid is equal to

A=\frac{1}{2}[BC+AD]AB

substitute the given values

A=\frac{1}{2}[50+25]25=937.5\ units^2

4 0
3 years ago
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