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2 years ago

I really need help please

Mathematics

1 answer:

Eddi Din [679]2 years ago

4 0

B.... I hope it helps

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Given the domain (-2,2,4) what is the range for the relation 3x-y=3

Bumek [7]

Answer:

Given the domain, the range for 3x-y = 3 is {-9, 6, 9}

Step-by-step explanation:

First you have to put the relation in terms of y ⇒ 3x - y = 3⇒ 3x -3 = y

⇒ y = 3x - 3.

Then you replace the values indicated by the domain to find their "y" values (the ones that constitute the range).

f(-2) = -9

f(2) = 6

f(4) = 9.

Finally, the range for the given domain is {-9, 6, 9}

3 0

2 years ago

An archaeologist at a dig sets up a coordinate system using string. Two similar artifacts are found one at position (1, 4) and t

myrzilka [38]

Given:

Positions of two artifacts are at points (1, 4) and (5, 2).

To find:

The distance between these two artifacts.

Solution:

Distance formula: The distance between two points is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, the distance between two points (1, 4) and (5, 2) is

$d=\sqrt{(5-1)^2+(2-4)^2}$

$d=\sqrt{(4)^2+(-2)^2}$

$d=\sqrt{16+4}$

$d=\sqrt{20}$

$d=4.4721359$

Round to the nearest tenth of a unit.

$d\approx 4.5$

Therefore, the distance between two artifacts is 4.5 units.

4 0

2 years ago

Please help with number 6 ASAP I will mark branlist

DerKrebs [107]

Answer:

<h2>12</h2><h2>Step-by-step explanation:</h2>

$4\sqrt{9}\\\\\mathrm{Factor\:the\:number:\:}\:9=3^2\\=4\sqrt{3^2}\\\\\mathrm{Apply\:radical\:rule}:\quad \sqrt{a^2}=a,\:\quad \:a\ge 0\\\sqrt{3^2}=3\\\\=4\times\:3\\\\=12$

5 0

2 years ago

How do U solve this?

Sonbull [250]

See photo for solution and mark me as brainliest if you think i helped!

4 0

2 years ago

Read 2 more answers

hi please help i’ll give brainliest if you give a correct answer (please show your long division on paper please :()

Vedmedyk [2.9K]

Answer:

Attached below

Step-by-step explanation:

sorry couldnt d it on paper ;)

3 0

2 years ago