Answer:
D) y = 12000 - 850x
Step-by-step explanation:
Given that the car is purchased for an initial value of $12,000 and depreciates each year at the same rate, you can set 'x' equal to the amount of time in years and -$850 for the rate at which it declines in price each year. If 'y' represents the total value of the car, than after so many years 'x', at a rate of -$850 per year, then the best model for this scenario is:
y = 12000 - 850x
There are infinitely many lines that have the point (1,-3).
A line can be expressed as:
y=mx+b, where m=slope and b=y-intercept..
Our only restriction is that it passes through (1,-3) so
-3=1m+b
So as long as the sum of the slope and the y-intercept is equal to -3, that is one of the infinite number of lines that passes through (1, -3)
So we could also say b=-3-m then our infinite lines are:
y=mx-3-m, now any real value of m creates a specific line that passes through the point. ie the first few are
y=x-4, y=2x-5, y=3x-6 or even y=x√2-3-√2
1. 9
2. 12
3. 9
4. 5
5. 5
6. 12
I believe
Answer:
72
Step-by-step explanation:
96 is 100%
100%-25%=75%
75÷100=0.75
0.75×96=72