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cricket20 [7]
2 years ago
6

Equations practice with angles Geometry. Can anyone help me please, im stuck....​

Mathematics
1 answer:
Bas_tet [7]2 years ago
3 0

Same as the last one ! Review your parallel lines, and you'll see that angles A and B have to be equal. So you solve it EXACTLY the same way as the last one.

You say "A equals B", and that means that

8x - 10 = 3x + 90

Solve that to find x (it's 20),

and then use x to find angle B (it's 150; they both are).

(Don't just take my word for it. Please work it through.)

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Find the measure of 7
fredd [130]

Answer:

126 degree

Step-by-step explanation:

use alternate angles and linear pair

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Find the volume. Help asap. Please.
alexgriva [62]

Use the Pythagorean theorem to find the diameter:

Diameter = √(19.3^2 - 9.5^2)

Diameter = √(372.49 - 90.25)

Diameter = √282.24

Diameter = 16.8 m

Volume of a cylinder = PI x r^2 x h

r = 1/2 diameter = 16.8 /2 = 8.4

h = 9.5 m

Volume = PI x 8.4^2 x 9.5

= PI x 70.56 x 9.5

= PI x 670.32

In terms of PI volume = 670.32PI

As a decimal:

670.32 x 3.14 = 2104.8048 = 2100m^3 ( rounded to the nearest hundred)

5 0
3 years ago
Read 2 more answers
In a sample of 53 walking canes, the average length was found to be 34.3in. with a variance of 1.9. Give a point estimate for th
Anna11 [10]

Answer:

1.38

Step-by-step explanation:

The point estimate for the population standard deviation of the length of the walking canes is given as the squareroot of variance. Since variance is provided as 1.9 then the standard deviation will be

\sqrt 1.9=1.37840487520902\approx 1.38

Therefore, rounded off to two decimal places, the standard deviation is approximately 1.38

6 0
3 years ago
Paula has her own business making cakes for
djverab [1.8K]

Answer:

Since Paula has her own business of making cakes for special occasions, and the total price (P) of one of Paula's cakes is represented by the equation P = 0.75S +10, where S is the number of people the cake serves, for determine what does the 0.75 represent in this situation and what does the 10 represent in this equation, the following mathematical reasoning must be carried out:

P is the price of the cake

S is the number of servings

Therefore, 0.75 is the value of each serving, which can be variable (the number of servings can vary)

In turn, 10 is the fixed cost of each cake.

4 0
3 years ago
A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 30 ft/s. Its height
Crank

Answer:

a) h = 0.1: \bar v = -11\,\frac{ft}{s}, h = 0.01: \bar v = -10.1\,\frac{ft}{s}, h = 0.001: \bar v = -10\,\frac{ft}{s}, b) The instantaneous velocity of the ball when t = 2\,s is -10 feet per second.

Step-by-step explanation:

a) We know that y = 30\cdot t -10\cdot t^{2} describes the position of the ball, measured in feet, in time, measured in seconds, and the average velocity (\bar v), measured in feet per second, can be done by means of the following definition:

\bar v = \frac{y(2+h)-y(2)}{h}

Where:

y(2) - Position of the ball evaluated at t = 2\,s, measured in feet.

y(2+h) - Position of the ball evaluated at t =(2+h)\,s, measured in feet.

h - Change interval, measured in seconds.

Now, we obtained different average velocities by means of different change intervals:

h = 0.1\,s

y(2) = 30\cdot (2) - 10\cdot (2)^{2}

y (2) = 20\,ft

y(2.1) = 30\cdot (2.1)-10\cdot (2.1)^{2}

y(2.1) = 18.9\,ft

\bar v = \frac{18.9\,ft-20\,ft}{0.1\,s}

\bar v = -11\,\frac{ft}{s}

h = 0.01\,s

y(2) = 30\cdot (2) - 10\cdot (2)^{2}

y (2) = 20\,ft

y(2.01) = 30\cdot (2.01)-10\cdot (2.01)^{2}

y(2.01) = 19.899\,ft

\bar v = \frac{19.899\,ft-20\,ft}{0.01\,s}

\bar v = -10.1\,\frac{ft}{s}

h = 0.001\,s

y(2) = 30\cdot (2) - 10\cdot (2)^{2}

y (2) = 20\,ft

y(2.001) = 30\cdot (2.001)-10\cdot (2.001)^{2}

y(2.001) = 19.99\,ft

\bar v = \frac{19.99\,ft-20\,ft}{0.001\,s}

\bar v = -10\,\frac{ft}{s}

b) The instantaneous velocity when t = 2\,s can be obtained by using the following limit:

v(t) = \lim_{h \to 0} \frac{x(t+h)-x(t)}{h}

v(t) =  \lim_{h \to 0} \frac{30\cdot (t+h)-10\cdot (t+h)^{2}-30\cdot t +10\cdot t^{2}}{h}

v(t) =  \lim_{h \to 0} \frac{30\cdot t +30\cdot h -10\cdot (t^{2}+2\cdot t\cdot h +h^{2})-30\cdot t +10\cdot t^{2}}{h}

v(t) =  \lim_{h \to 0} \frac{30\cdot t +30\cdot h-10\cdot t^{2}-20\cdot t \cdot h-10\cdot h^{2}-30\cdot t +10\cdot t^{2}}{h}

v(t) =  \lim_{h \to 0} \frac{30\cdot h-20\cdot t\cdot h-10\cdot h^{2}}{h}

v(t) =  \lim_{h \to 0} 30-20\cdot t-10\cdot h

v(t) = 30\cdot  \lim_{h \to 0} 1 - 20\cdot t \cdot  \lim_{h \to 0} 1 - 10\cdot  \lim_{h \to 0} h

v(t) = 30-20\cdot t

And we finally evaluate the instantaneous velocity at t = 2\,s:

v(2) = 30-20\cdot (2)

v(2) = -10\,\frac{ft}{s}

The instantaneous velocity of the ball when t = 2\,s is -10 feet per second.

8 0
3 years ago
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