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2 years ago

6

Equations practice with angles Geometry. Can anyone help me please, im stuck....

1 answer:

Bas_tet [7]2 years ago

3 0

Same as the last one ! Review your parallel lines, and you'll see that angles A and B have to be equal. So you solve it EXACTLY the same way as the last one.

You say "A equals B", and that means that

8x - 10 = 3x + 90

Solve that to find x (it's 20),

and then use x to find angle B (it's 150; they both are).

(Don't just take my word for it. Please work it through.)

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Marianna [84]

Answer:

3

Step-by-step explanation:

Get rid of fractions:

Multiply the whole equation, i.e. all terms both sides of the equals sign, by the denominator or the lowest common multiple of all denominators if there are multiple fractions in the equation;

In this case, only one term is a fraction and therefore has a denominator (i.e. 7), so it is this number we multiply the equation by to get:

7(y) = 7(-³/₇.x) + 7(3)

7y = -3x + 21

3x + 7y = 21

5 0

2 years ago

No clue how to do this.

tatiyna

Answer:

Look at the graph, on the left side it says snow on the ground, and it starts on 5, as the storm continued more fell. nvm.

Step-by-step explanation: The answer to your question is 5, because that is how much is on the ground at the beggining.

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2 years ago

Read 2 more answers

Can you answer these please many thanks

givi [52]

Given: (a) $2(x+3)=2x+6$ and (b) $4(y-3)=4y-12$ .

To find: The expanded form of the given expressions.

(c) $4(m+n)=4m+4n$ (using $a(b+c)=ab+ac$ )

(d) $3(5-q)=15-3q$ (using $a(b-c)=ab-ac$ )

(e) $5(2c+1)=10c+5$ (using $a(b+c)=ab+ac$ )

(f) $3(2x-5)=6x-15$ (using $a(b-c)=ab-ac$ )

(g) $7(4b-1)=28b-7$ (using $a(b-c)=ab-ac$ )

(h) $3(2x+y-5)=3((2x+y)-5)$

⇒ $3(2x+y-5)=3(2x+y)-15$ (using $a(b-c)=ab-ac$ )

⇒ $3(2x+y-5)=6x+3y-15$ (using $a(b+c)=ab+ac$ )

(i) $2(6a-4b+3)=2((6a-4b)+3)$

⇒ $2(6a-4b+3)=2(6a-4b)+6$ (using $a(b+c)=ab+ac$ )

⇒ $2(6a-4b+3)=12a-8b+6$ (using $a(b-c)=ab-ac$ )

(j) $6(m+n+p)=6((m+n)+p)$

⇒ $6(m+n+p)=6(m+n)+6p$ (using $a(b+c)=ab+ac$ )

⇒ $6(m+n+p)=6m+6n+6p$ (using $a(b+c)=ab+ac$ )

(k) $y(y+2)=y^2+2y$ (using $a(b+c)=ab+ac$ )

(l) $g(g-3)=g^2-3g$ (using $a(b-c)=ab-ac$ )

(m) $n(4-n)=4n-n^2$ (using $a(b-c)=ab-ac$ )

(n) $a(b+c)=ab+ac$ (using $a(b+c)=ab+ac$ )

(o) $s(3s-4)=3s^2-4s$ (using $a(b-c)=ab-ac$ )

(p) $2x(x+5)=2x^2+10x$ (using $a(b+c)=ab+ac$ )

(q) $4y(x-3)=4xy-12y$ (using $a(b-c)=ab-ac$ )

(r) $5a(2b-5)=10ab-25a$ (using $a(b-c)=ab-ac$ )

(s) $4a(3b+2c)=12ab+8ac$ (using $a(b+c)=ab+ac$ )

(t) $5p(4p-5q)=20p^2-25pq$ (using $a(b-c)=ab-ac$ )

6 0

3 years ago

Michelle bought two blouses for $18.20 each. If she received a 10% discount for the blouses and the sales tax rate is 7.25%, how

Gnesinka [82]

The answer is B. $17.57

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2 years ago

A person's Body Mass Index (BMI) is a measure of the mount of fat in their body. The relationship between antioxidant food consu

loris [4]

Answer:

Check explanation

Step-by-step explanation:

Given:

y = -0.1x + 22

Where,

y = BMI of an individual

x = antioxidant food consumption per day in cups

Equation of a slope

y = mx + c

Where,

m = slope

c = y - intercept

Therefore,

From the equation

y = -0.1x + 22

slope, m = -0.1

y - intercept, c = 22

4 0

2 years ago