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Xy = -14
x + y = -3
x + y = -3
2.53 + y = -3
- 2.53 - 2.53
y = -5.53
(x, y) = (2.53, -5.53)
x + y = -3
-5.53 + y = -3
+ 5.53 + 5.53
y = 2.53
(x, y) = (-5.53, 2.53)
The two numbers that multiply to -14 and add up to -3 are -5.53 and 2.53.
x + y = -3
x + y = -3
2.53 + y = -3
- 2.53 - 2.53
y = -5.53
(x, y) = (2.53, -5.53)
x + y = -3
-5.53 + y = -3
+ 5.53 + 5.53
y = 2.53
(x, y) = (-5.53, 2.53)
The two numbers that multiply to -14 and add up to -3 are -5.53 and 2.53.
The given equation is:
To find the line perpendicular to it, we interchange coefficients and switch the signs of one coefficient.
The equation to a line perpendicular to it is:
$ 2y-x=c$
where, $c$ is some constant we have determine using the condition given.
It passes through $(2,-1)$
Put the point in our equation:
$2(-1)-(2)=c$
$c=-2-2$
$c=-4$
The final equation is:
$\boxed{ 2y-x=-4}$