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alexdok [17]
3 years ago
5

For 6 consecutive days, Alejandro studied for 5 minutes more each day than he did the previous day. Which best represents the ch

ange in the amount of time that Alejandro studied on the first day to the amount of time he studied on the last day? –30 minutes –11 minutes 11 minutes 30 minutes
Mathematics
2 answers:
xeze [42]3 years ago
6 0

Answer:

30 minutes

Step-by-step explanation:

77julia77 [94]3 years ago
5 0

Answer:

it is on ed it is 30

Step-by-step explanation:

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Help me solve this please
LuckyWell [14K]

9514 1404 393

Answer:

  shaded/square = (50π cm²)/(400 cm²) = π/8

Step-by-step explanation:

The quarter circle has area ...

  A = (1/4)(πr²) = π/4(20 cm)² = 100π cm²

The half-circle has area ...

  A = (1/2)(πr²) = π/2(10 cm)² = 50π cm²

Then the area of the shaded portion is ...

  shaded = 100π cm² -50π cm² = 50π cm²

__

The area of the square is ...

  A = s² = (20 cm)² = 400 cm²

Then the ratio of interest is ...

  shaded/square = (50π cm²)/(400 cm²) = π/8

5 0
4 years ago
Which of the following represents a function?
steposvetlana [31]

Answer:

a

Step-by-step explanation:

bc its the only one that makes sence to me heheh

7 0
3 years ago
Read 2 more answers
• How do I isolate a variable?
irga5000 [103]
Depends on the question but you generally must use a variety of operations to isolate the variable by itself on one side of the equation
8 0
3 years ago
Read 2 more answers
Which is equivalent to sin 51°?<br> A- cos 51<br> B- cos 39<br> C- tan 39<br> D- tan 51
fomenos

Answer:

Ans = B

Step-by-step explanation:

The answer is B

Have a great day

5 0
3 years ago
Suppose you start out with a cone of height 8 cm and base radius 6 cm, and you want to change the dimensions in such a way that
NARA [144]

Answer: r ≈ 5.95

Step-by-step explanation:

Let S be the surface area , then

S = \pir^{2} + \pir\sqrt{r^{2}+h^{2}}

Differentiating S with respect to r , we have

dS = \frac{dS}{dr} dr + \frac{dS}{dh} dh

\frac{dS}{dr} = (2\pir +\pi\sqrt{h^{2}+r^{2}} + \frac{\pi r^{2} }{\sqrt{h^{2}+r^{2}} }) dr + \frac{\pi rh }{h^{2}+r^{2}  } dh

For the area to remain the same it means dS = 0

since r = 6cm , h = 8cm , dh = 0.28 then we have

0 = (12π + 10π +\frac{18\pi }{5})dr + \frac{24\pi }{5} X 0.28.

Making dr the subject of formula , we have

(12π + 10π +\frac{18\pi }{5})dr = - (\frac{24\pi }{5} X 0.28)

(\frac{128\pi }{5}) dr = - \frac{6.72\pi }{5}

(640\pi)dr = - 33.6\pi

dr = - 33.6\pi / 640\pi

dr = 0.05

This means that the radius should decrease by 0.05 for the area to remain the same. That means the radius = 6 - 0.05

r ≈ 5.95

7 0
3 years ago
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