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3 years ago

Only answer if you know pls

Mathematics

1 answer:

STALIN [3.7K]3 years ago

8 0

Answer:

Step-by-step explanation:

We know: the sum of the measures of triangle angles is 180°.

Therefore we have the equation:

$(4x-13)+15+(x+18)=180$ <em>combine like terms</em>

$(4x+x)+(-13+15+18)=180$

$5x+20=180$ <em>subtract 20 from both sides</em>

$5x=160$ <em>divide both sides by 5</em>

$x=32$

$m\angle A=(4x-13)^o\\\\m\angle C=(x+18)^o$

Substitute:

$m\angle A=(4\cdot32-13)^o=(128-13)^o=115^o\\\\m\angle C=(32+18)^o=50^o$

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3 years ago

Read 2 more answers

Given: ΔACM, m∠C = 90º

Virty [35]

Answer:

CM=20 and CP=12

Step-by-step explanation:

The given triangle ΔACM has the measurements as follows:

m∠C=90°, CP⊥AM, AC=15, AP=9, PM=16.

To Find: CP and CM

We can use Pythagoras theorem to calculate the sides CP and CM.

Pythagoras theorem gives a relation between hypotenuse, base and height/perpendicular of a right angled triangle which is as follows:

$h^{2}=p^{2}+b^{2}$

where h is hypotenuse of triangle, b is base and p is perpendicular of triangle.

The figure shows that in ΔACM is a right angled triangle at C where,

AM --> hypotenuse

CM --> base

AC --> height

So substituting values into formula:

$AM^{2}=AC^{2}+CM^{2}$

$25^{2}=15^{2}+CM^{2}$

$625-225=CM^{2}$

$400=CM^{2}$

$\sqrt{400} =CM$

$CM=20$ , which is required answer.

Similarly, we can see that triangle ΔCPM is also a right angled triangle at P and thus Pythagoras theorem can again be applied to calculate CP. Since CM is the side opposite to right angle P, it is the hypotenuse.

So we have,

$CM^{2}=PM^{2}+CP^{2}$