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3 years ago

which is the correct simplified version of the expression shown after distrubuting and combining like terms? 1/3(9x-15)+2x

Mathematics

1 answer:

zhannawk [14.2K]3 years ago

7 0

Answer:11x + 5

Step-by-step explanation:1/3 times 9X is 3x. 1/3 times 15 is 5. Now you have 9x + 5 + 2x

9x + 2x = 11x

Final answer: 11x + 5

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Question 2(Multiple Choice Worth 4 points) (08.02)A pair of equations is shown below. x + y = 5 y = one halfx + 2 If the two equ

8_murik_8 [283]

Answer:

$(2,3)$

Step-by-step explanation:

The first equation is $x+y=5$

The second equation is $y=\frac{1}{2}x+2$

When we graph these two equations, <em>they will meet at a point which represent the solution of the two equations</em>.

We can solve the two equations simultaneously to determine their point of intersection.

Let us substitute the second equation into the first equation to get;

$x+\frac{1}{2}x+2=5$

Multiply through by 2 to get;

$2x+x+4=10$

Group similar terms to obtain;

$2x+x=10-4$

Simplify;

$3x=6$

Divide both sides by 3;

$\Rightarrow x=2$

Put $x=2$ into the second equation;

$y=\frac{1}{2}(2)+2$

$\Rightarrow y=1+2$

$\Rightarrow y=3$

Therefore the graphs of the two functions intersect at (2,3)

See graph in attachment.

3 0

2 years ago

If a translation maps point (3, 2) to (5,3); or T:(3, 2) - (5,3), indicate the image for (2,4)

Zinaida [17]

Answer:

Step-by-step explanation:

Note that for (3, 2) → (5, 3)

The x- coordinate of the image is 2 more (+ 2) than the original and the y- coordinate of the image is 1 more (+ 1) than the original, that is

(x, y ) → (x + 2, y + 1 ) ← rule to obtain image, hence

(2, 4 ) → (2 + 2, 4 + 1 ) → (4, 5 ) → A

6 0

2 years ago

please help me, Prove a quadrilateral with vertices G(1,-1), H(5,1), I(4,3) and J(0,1) is a rectangle using the parallelogram me

mestny [16]

Answer:

Step-by-step explanation:

We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).

Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are equal, thus

Join JH and GI such that they form the diagonals of the quadrilateral.Now,

JH= $\sqrt{(5-0)^{2}+(1-1)^{2}}=5$ and

GI= $\sqrt{(4-1)^{2}+(3+1)^{2}}=5$

Now, mid point of JH= $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

= $(\frac{5+0}{2},\frac{1+1}{2})=(\frac{5}{2},1)$

Mid point of GI= $(\frac{5}{2},1)$

Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.

Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.

Thus, From ΔGIJ, we have

$(GI)^{2}=(IJ)^{2}+(JG)^{2}$ (1)

Now, JI= $\sqrt{(4-0)^{2}+(3-1)^{2}}=\sqrt{20}$ and GJ= $\sqrt{(0-1)^{2}+(1+1)^{2}}=\sqrt{5}$

Substituting these values in (1), we get

$5^{2}=(\sqrt{20})^{2}+(\sqrt{5})^{2} }$

$25=20+5$

$25=25$

Thus, GIJ is a right angles triangle.

Hence, GHIJ is a rectangle.

Also, The diagonals GI= $\sqrt{(4-1)^{2}+(3+1)^{2}}=5$ and HJ= $\sqrt{(0-5)^2+(1-1)^2}=5$ are equal, thus, GHIJ is a rectangle.

6 0

2 years ago

Simplify the expression:

krek1111 [17]

Answer:

235a is 1

235b is a^12k+4 i think

3 0

2 years ago

Which of the following shows the division problem below in synthetic division

alexandr402 [8]

Answer:

The Answer is C

Step-by-step explanation:

Look at each coefficient next to the degree of the radical. When inputting that number for synthetic division (From greatest degree to least) you would get 8 1 and -5. The number that is the divisor is the 6, but you have to set (x - 6) to equal zero, which would get you a number of 6.

7 0

3 years ago

Read 2 more answers

which is the correct simplified version of the expression shown after distrubuting and combining like terms? 1/3(9x-15)+2x​

which is the correct simplified version of the expression shown after distrubuting and combining like terms? 1/3(9x-15)+2x