20 ounces to 25 ounces. What's the percent change.

Write an equation from the information given: A rectangle is twice as long as it is wide. The perimeter of the rectangle is 18.

Agata [3.3K]

Let width = x, Therefore the length must equal 2x

Therefore insert these values on the sides of a rectangle.

Add: 2x + 2x + x + x = 18

Therefore 6x = 18

x = 3

3 0

3 years ago

The graph of a function must be linear if it has what characteristic?

mario62 [17]

The graph of a function must be linear if x is not squared in the function

3 0

3 years ago

Read 2 more answers

An isosceles right triangle has an area 8 cm square find the length of its hypotenuse

Ainat [17]

Answer:

5.9

Step-by-step explanation:

Area of a triangle is 1/2 base times height. the base is the horizontal part of the triangle and the height is the vertical part. Since it a isosceles they are equal. Those two segment are also called the legs (remember that for later). 4x4=16 times 1/2 equal 8 cm squared. So know me must find the hypotenuse. Since we since dealing with a right triangle we are going to use pythagorean theorem which is

${a}^{2} + {b}^{2} = {c}^{2}$

where a and b are the LEGS and c is the hypotenuse. the legs are also known as base and height so we use

${4}^{2} + {4}^{2} = {c}^{2}$

which simplify to

$16 + 16 = {c}^{2}$

$32 = {c}^{2}$

$\sqrt{32}$

which is about 5.9

6 0

3 years ago

A Rectangle with sides 100m and 50m. Person B and Person A start walking in the opposite direction at the same point with veloci

Maurinko [17]

Answer:

It takes takes them 31.67 secs to meet after Person A starts walking

OR

34.67 secs after Person B starts walking

Step-by-step explanation:

First, we will find the perimeter of the rectangle

From,

Perimeter of rectangle = 2 ( $l$ + $b$ )

Where $l$ is the length

and $b$ is the breadth

From the question, $l$ = 100m

and $b$ = 50m

Hence,

Perimeter of the rectangle = 2 (100+50)

= 2(150) = 300m

Hence, the perimeter of the rectangle is 300m

This is the total distance that will be covered by both persons by the time they meet.

Let the distance covered by person A be $S_{1}$

and the distance covered by person B be $S_{2}$

We can write that

$S_{1}$ + $S_{2}$ = 300m

Velocity of person A, $V_{A}$ = 4 m/s

and velocity of person B, $V_{B}$ = 5 m/s

From the question, Person A starts walking 3 seconds after person B,

This means, if person A spends $t$ secs before they meet, then person B would spend (3 + $t$ ) secs.

For Person A,

Velocity = 4 m/s

Time = $t$ secs

Distance = $S_{1}$

From,

$Velocity = \frac{Distance}{Time}$

Then,

$Distance = Velocity \times time$

$S_{1} = 4 \times t$

$S_{1} = 4t$ ...... (1)

For Person B

Velocity = 5 m/s

Time = (t + 3) secs

Distance = $S_{2}$

Also, from

$Distance = Velocity \times time$

$S_{2} = 5 \times (3+t)$

$S_{2} = 5(3+t)$ ...... (2)

Recall that, $S_{1}$ + $S_{2}$ = 300m

Then, $S_{2}$ = 300m - $S_{1}$

We can then write that,

300m - $S_{1}$ $= 5(3+t)$

Then,

$S_{1} = 300 - 5(3+t)$ ..... (3)

Equating equations (1) and (3), we get

$300 - 5(3+t) = 4t$

$300 - 15 -5t = 4t\\9t = 285\\t = \frac{285}{9}\\$

$t = 31.67 secs$

This is the time spent by Person A

Hence, it takes takes them 31.67 secs to meet after Person A starts walking OR

34.67 secs after Person B starts walking

3 0

3 years ago

Inequality for 3x+1>x-1

Diano4ka-milaya [45]

Answer:

x>-1

Step-by-step explanation:

solve this normally like a linear equation

3x + 1 >x-1

collect like terms

3x-x>-1-1

2x>-2

x>-2/2

x>-1

5 0

2 years ago