Answer:for ax^2+bx+c=0 the discriminant is b^2-4ac
there are 3 basic cases of what happens for different discriminants
1. if the discriminant is less than 0, then there are no real zeroes
2. if the discriminant is 0, then it has 1 zero
3. if the discriminant is greater than 0, it has 2 zeroes
so given
0=3x^2-7x+4
a=3,b=-7,c=4
thus the discriminant is (-7)^2-4(3)(4)=49-48=1
the discriminant is 1. 1 is positive, thus the equation has 2 zeroes because the discriminant is greater than 0
the answer is the equation has two zeroes because the discriminant is greater than 0
Step-by-step explanation:
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Answer:
If you are doing subtraction with fractions you need to make a common denominator and subtract the numerators from each other
ex. 1/2 - 1/3
make a common denominator (or find the least common multiple)
3/6 - 2/6
subtract the numerators
take 2 from 3 and put that on top.
Solution 1/2-1/3= 3/6-2/6= 1/6
Answer:
y = -¼│x − 5│+ 3
Step-by-step explanation:
y = a│x − h│+ k
(h, k) is the vertex of the absolute value graph. In this case, it's (5, 3).
y = a│x − 5│+ 3
One point on the graph is (1, 2). Plug in to find the value of a.
2 = a│1 − 5│+ 3
2 = 4a + 3
a = -¼
Therefore, the graph is:
y = -¼│x − 5│+ 3
