Dianne drew a triangle in math class.

If a store credit account charges 1.5% interest each<br> month, what is the APR?

Anuta_ua [19.1K]

The APR is the annual percentage rate
therefore the APR is 1.5x12=18%

6 0

3 years ago

A train has a ratio of 5:6 men to women. At a stop 8 men get off the train. The ratio of men to women is now 3:4. How many peopl

Tju [1.3M]

Answer:

See the attachment

Step-by-step explanation:

8 0

3 years ago

a teacher has three packages of crayons. one package contains 52 crayons, another contains 12 crayons, and the third package con

kotegsom [21]

Answer: 7 crayons

Step-by-step explanation:

To solve we first must find the total number of crayons available by adding up how many crayons are in each container.

56+12+96 = 160 crayons total

Next we take this number and divide it by 22 (the number of students in the class) to determine how many crayon each student gets

160 crayons/22 students = 7.272727 crayons per student

However, it's important to note that this number is not a whole number. We must then round down to the nearest whole number because students aren't given fractions of crayons.

7.272727 ==> 7 crayons per student

5 0

1 year ago

An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh

natima [27]

Answer:

Speed of the plane in still air: $779\; {\rm km \cdot h^{-1}}$ .

Windspeed: $100\; {\rm km \cdot h^{-1}}$ .

Step-by-step explanation:

Assume that $x\; {\rm km \cdot h^{-1}}$ is the speed of the plane in still air, and that $y\; {\rm km \cdot h^{-1}}$ is the speed of the wind.

When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be $(x - y)\; {\rm km \cdot h^{-1}}$ .
When this plane is travelling in the same direction as the wind, the ground speed of this plane would be $(x + y)\; {\rm km \cdot h^{-1}}$ .

The question states that when going against the wind ( $v = (x - y)\; {\rm km \cdot h^{-1}}$ ,) the plane travels $6111\; {\rm km}$ in $9\; {\rm h}$ . Hence, $9\, (x - y) = 6111$ .

Similarly, since the plane travels $7911\; {\rm km}$ in $9\; {\rm h}$ when travelling in the same direction as the wind ( $v = (x + y)\; {\rm km \cdot h^{-1}}$ ,) $9\, (x + y) = 7911$ .

Add the two equations to eliminate $y$ . Subtract the second equation from the first to eliminate $x$ . Solve this system of equations for $x$ and $y$ : $x = 779$ and $y = 100$ .

Hence, the speed of this plane in still air would be $779\; {\rm km \cdot h^{-1}}$ , whereas the speed of the wind would be $100\; {\rm km \cdot h^{-1}}$ .

3 0

1 year ago

A part selected for testing is equally likely to have been produced on any one of six cutting tools.

JulijaS [17]

Answer:

a)S= (1,2,3,4,5,6)

b) 1/6 or 16.67%

c) 1/3 or 33.33%

d) 5/6 or 83.33%

Step-by-step explanation:

a) Sample space is the list of all the possible sample in this its either tool 1,2,3,4,5 or 6

b) probability of selecting from tool 1 is equally likely to picking from any cutting tool therefore it

1/6 or 16.7%

c) probability of selecting from any tool is 16.7% so probability of selecting from 3 or 5 = 16.67% + 16.67% = 33.3%

d) if the part is not from tool 4 then its from tool 1, or tool 2 or tool 3 or tool 5 or tool 6 therefore its

1/6+1/6+1/6+1/6+1/6 = 5/6 or 8.33%

8 0

3 years ago