3 years ago

Given the equation f(x) = (x + 3)2 – 8, fill in the blanks:

1 answer:

4 0

Quadratic f(x) = (x -h)² +k has vertex (h, k) and axis of symmetry x=h. When k is negative, the number of real solutions is 2, because both branches of the function cross the x-axis.

In your equation, h = -3 and k = -8.

Axis of symmetry: x = -3
Vertex: (-3, -8)
Number of real solutions: 2

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shepuryov [24]

Answer:

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Paraphin [41]

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3 years ago

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quester [9]

Answer:

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Step-by-step explanation:

The trig identity for the differnce of angles tells you ...

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We are given that sin(A) = 4/5 in quadrant II, so cos(A) = -√(1-(4/5)^2) = -3/5.

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sin(A-B) = (4/5)(3/5) -(4/5)(-3/5) = 12/25 + 12/25 = 24/25

The desired sine is 24/25.

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3 years ago

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earnstyle [38]

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2 1/2

Step-by-step explanation:

Hope this helps :P

Have a great day!

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