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3 years ago

Convert 20 milligrams into grams. Can somebody help ?

Mathematics

2 answers:

Fantom [35]3 years ago

4 0

Answer:

0.02

Step-by-step explanation:

Margarita [4]3 years ago

3 0

Answer:

20 = 0.02

milligrams gram

Step-by-step explanation:

divide the mass value by 1000

i study

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At what point does the curve have maximum curvature? Y = 4ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as

MAXImum [283]

Answer-

At $x= \frac{1}{2304e^4-16e^2}$ the curve has maximum curvature.

Solution-

The formula for curvature =

$K(x)=\frac{{y}''}{(1+({y}')^2)^{\frac{3}{2}}}$

Here,

$y=4e^{x}$

Then,

${y}' = 4e^{x} \ and \ {y}''=4e^{x}$

Putting the values,

$K(x)=\frac{{4e^{x}}}{(1+(4e^{x})^2)^{\frac{3}{2}}} = \frac{{4e^{x}}}{(1+16e^{2x})^{\frac{3}{2}}}$

Now, in order to get the max curvature value, we have to calculate the first derivative of this function and then to get where its value is max, we have to equate it to 0.

${k}'(x) = \frac{(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})}{(1+16e^{2x} )^{2}}$

Now, equating this to 0

$(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x}) =0$

$\Rightarrow (1+16e^{2x})^{\frac{3}{2}}-(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})$

$\Rightarrow (1+16e^{2x})^{\frac{3}{2}}=(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})$

$\Rightarrow (1+16e^{2x})^{\frac{1}{2}}=48e^{2x}$

$\Rightarrow (1+16e^{2x})}=48^2e^{2x}=2304e^{2x}$

$\Rightarrow 2304e^{2x}-16e^{2x}-1=0$

Solving this eq,

we get $x= \frac{1}{2304e^4-16e^2}$

∴ At $x= \frac{1}{2304e^4-16e^2}$ the curvature is maximum.

6 0

2 years ago

Idk what to do here?

creativ13 [48]

1 box =1 foot so you would have to count the boxes away from her

7 0

2 years ago

Read 2 more answers

Two boys are running track. They decide to start in the northwest corner and go opposite directions around the rectangular track

Mariulka [41]

= 187.3 yards

Step-by-step explanation:

The set-up will represent a triangle whereby the :

Width = Height = 150 yards
Diagonal = Hypotenuse = 240 yards
Length = Base = ?

${a}^{2} = {c}^{2} - {b}^{2} \\ {a}^{2} = {240}^{2} - {150}^{2} \\ {a}^{2} = 57600 - 22500 \\ \sqrt{ {a}^{2} } = \sqrt{35100} \\ a = 187.3yards \: (rounded \: off \: to \: 1dp)$

3 0

2 years ago

Hello! Can you please help me on these two problems? =)

poizon [28]

Yeah, I gotta read the questions better.

Perimeter not area.

diagonal length = √((28 - 12)² + (24 - 10)²) = 21.26

P = 12 + 10 + 28 + 24 + 21.26 = 95.26 units

sphere surface area = 4πR²

R = √(379.94 / 4(3.14) = 5.5 in

D = 2R = 11 inch

4 0

3 years ago

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!! Show your work

cestrela7 [59]

Well start with reflecting abc over the y axis

7 0

2 years ago