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2 years ago

MATH HELP ASSAP! MAKING BRAINLIST! QUESTION IN PIC

Mathematics

1 answer:

Doss [256]2 years ago

4 0

Answer:

The answed is a function

Step-by-step explanation:

Since there is one value of y for every value of x in the data the realtion is a function

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Plz help I’ll mark you

timurjin [86]

Answer:

A 1/2

Step-by-step explanation:

Ratio of short length to hypotenuse

= cos60

= 1/2

4 0

2 years ago

Recall from Intermediate Algebra that two non-vertical lines are perpendicular if and only if they have negative reciprocal slop

OLEGan [10]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The line is $y = -4 x$

Step-by-step explanation:

From the question we are told that

The line is $y = \frac{1}{4} x + 8$

The point is P(0,0 )

Generally the equation for a line is $yn = mx + c$

Now comparing this with the given equation we see that

$m =\frac{1}{4} = slope$

$C =8 = intercept$

Generally the slope of the perpendicular to the given line is mathematically evaluated as

$m_1 = - \frac{1}{m}$

=> $m_1 = - \frac{1}{ \frac{1}{4}}$

=> $m_1 = -4$

Generally from the univesal equation of a line and the given point we have that

y = mx + c at p(0,0) and $m_1 = -4$ is

0 = -4 (0 ) + c

=> c = 0

Hence the equation perpendicular to the line given at the point given is

$y = -4 x$

8 0

2 years ago

What are the roots of the quadratic equation 2x2+7x+4=0? Select all that apply.

skad [1K]

Answer:

option A and B

$x=\frac{-7+\sqrt{17}} {4}$

and

$x=\frac{-7-\sqrt{17}} {4}$

Step-by-step explanation:

we have

$2x^2+7x+4=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$2x^2+7x+4=0$

$a=2\\b=7\\c=4$

substitute in the formula

$x=\frac{-7\pm\sqrt{7^{2}-4(2)(4)}} {2(2)}$

$x=\frac{-7\pm\sqrt{17}} {4}$

$x=\frac{-7+\sqrt{17}} {4}$

and

$x=\frac{-7-\sqrt{17}} {4}$

7 0

2 years ago

Simplify 1/a+b + 1/a-b + 2b/a^2-b^2

Simora [160]

Answer:

−a^2 b^2 + 2a + 2b

_________________

a^2

Step-by-step explanation:

<u><em>Please mark as brainliest if answer is right</em></u>

Have a great day, be safe and healthy

Thank u

8 0

2 years ago

What are the sine, cosine, and tangent of Θ = 3 pi over 4 radians?

Daniel [21]

Our angle teta is:
teta = 3pi/4

since that is larger than pi/2 but less than pi that means that our angle lies in II quadrant (x negative y positive)

sin(3pi/4) = √2/2
cosine and tangent of that angle must be negative because of position of the angle.

cos(3pi/4) = -√2/2
tan(3pi/4) = -1

7 0

3 years ago