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Sophie [7]
3 years ago
10

HELP PLZ!!!! A courtyard in the shape of a right triangle is set in the middle of three square office buildings, with one office

building along each side. Which statement is true about the three office buildings?

Mathematics
2 answers:
BigorU [14]3 years ago
8 0
Its A (The area of Building C minus the area of Building B equals the area of Building A)
8_murik_8 [283]3 years ago
5 0
The area of building C minus the area of building B equals the area of building A because of Pythagorean Theorem.<span />
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(-1)3 exponet is 3 help me please i dont want to fail
Natali5045456 [20]

Answer:

-1

i do not remember how to solve this but i just answered a question that had this problem in it on my algebra test and that is the right answer

8 0
3 years ago
You have 23 1/2 pounds of blueberries to store in freezer bags. Each bag holds 3 3/4 pounds of blueberries. What is the minimum
monitta

Answer:

The minimum number of freezer bags needed to store all the blueberries is 7

Step-by-step explanation:

we know that

To find out the number of freezer bags needed , divide the total pounds of blueberries by 3 3/4, but first convert mixed number to an improper fraction

23\frac{1}{2}\ lb=\frac{23*2+1}{2}=\frac{47}{2}\ lb

3\frac{3}{4}\ lb=\frac{3*4+3}{4}=\frac{15}{4}\ lb

\frac{47}{2}:\frac{15}{4}=\frac{47*4}{2*15} =\frac{94}{15}=6.3\ bags

Round up

7 bags

therefore

The minimum number of freezer bags needed to store all the blueberries is 7

7 0
3 years ago
Find limit as x approaches 2 from the left of the quotient of the absolute value of the quantity x minus 2, and the quantity x m
Molodets [167]

Answer:

\lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

Step-by-step explanation:

We want to find \lim_{x \to 2^-} \frac{|x-2|}{x-2}.

By definition:

|x-2|=\left \{ {{x-2,\:if\:x\:>\:2} \atop {-(x-2),\:if\:x\:

Since we want to find the Left Hand Limit, we use f(x)=-(x-2)

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} \frac{-(x-2)}{x-2}.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} (-1).

The limit of a constant is the constant.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

8 0
3 years ago
Describe the number and type of roots for the polynomial. (how many real and complex?)
DENIUS [597]
This is a cubic equation  so it will have a total of three roots.
there is only one change of sign  so the equation will have one positive real  root.
The other 2 roots  will be negative  and might be real or complex
7 0
3 years ago
Jake ate 4/8 of a pizza. Millie ate 3/8 of the same pizza. How much of the pizza was eaten by jake and Millie?
Alexus [3.1K]
I believe they both had 7/8
3 0
3 years ago
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