Answer:
4(k - 3)(3k + 5)
Step-by-step explanation:
Given
12k² - 16k - 60 ← factor out 4 from each term
= 4(3k² - 4k - 15) ← factor the quadratic
Consider the factors of the product of the coefficient of the k² term and the constant term which sum to give the coefficient of the k term
product = 3 × - 15 = - 45 , sum = - 4
Factors are - 9 and + 5
Use these factors to split the middle term
3k² - 9k + 5k - 15 → ( factor the first/second and third/fourth terms
= 3k(k - 3) + 5(k - 3) ← factor out (k - 3)
= (k - 3)(3k + 5)
Hence
12k² - 16k - 60 = 4(k - 3)(3k + 5) ← in factored form
Answer:
x=13,y=0
Step-by-step explanation:
We are given a system of equations
For equation 1,square all terms to reduce it
√x²+√y²=169
x+y=13
Make x the subject as required by the question to use substitution method
x=13-y
Plug x=13-y into eqn 2
3(13-y)+2y=39
39-3y+2y=39
39-y=39
y=39-39=0
Plug y=0 into equation 1
x+0=13
x=0
Answer:
The answer is line D
Step-by-step explanation:
See picture for solution to your problem.
Since the variable x is at the exponent, this is an exponential function.
To decide whether an exponential function is a growing or decaying one, we have to look at the base of the exponent.
If the base is between 0 and 1, we have exponential decay
If the base is larger than 1, we have exponential growth.
In your case the base is 3, which is larger than 1, so you have exponential growth.
Thus, <u>option d</u> is your answer
