If we know that two sets of corresponding angles and the corresponding included sides are congruent in two triangles, what can we say about the triangles?
Hey
The Answer is -4x
Heres the Step by Step work
You add 14 to each side because it is negative, so
5x-14=-34
+14|+14
and you will end up with
5x=-20
Divide 5 on each side, so
5x=-20
/5x | /5x
-20 / 5x =
x=-4
or
-4x
mark branliest plz
Answer:
x = -2 or x = 1/3 thus: B & C
Step-by-step explanation:
Solve for x over the real numbers:
2 x^2 + 7 x - 2 = 2 x - x^2
Subtract 2 x - x^2 from both sides:
3 x^2 + 5 x - 2 = 0
The left hand side factors into a product with two terms:
(x + 2) (3 x - 1) = 0
Split into two equations:
x + 2 = 0 or 3 x - 1 = 0
Subtract 2 from both sides:
x = -2 or 3 x - 1 = 0
Add 1 to both sides:
x = -2 or 3 x = 1
Divide both sides by 3:
Answer: x = -2 or x = 1/3
Answer:
1. 3rd degree
2. No degree
3. First degree
4. 8th degree
Step-by-step explanation:
Hope this helps!
Answer:
-4, -6, -3, -5, -1. The inequality solved for n is n ≥ -6.
Step-by-step explanation:
Substitute all the values in the equation.
n/2 ≥ -3
-10/2 ≥ -3
-5 is not ≥ -3.
n/2 ≥ -3
-7/2 ≥ -3
-3.5 is not ≥ -3.
n/2 ≥ -3
-4/2 ≥ -3
-2 is ≥ -3.
n/2 ≥ -3
-9/2 ≥ -3
-4.5 is not ≥ -3.
n/2 ≥ -3
-6/2 ≥ -3
-3 is ≥ -3.
n/2 ≥ -3
-3/2 ≥ -3
-1.5 is ≥ -3.
n/2 ≥ -3
-8/2 ≥ -3
-4 is not ≥ -3.
n/2 ≥ -3
-5/2 ≥ -3
-2.5 is ≥ -3.
n/2 ≥ -3
-2/2 ≥ -3
-1 is ≥ -3.
To solve the inequality n/2 ≥ -3 for n, do these steps.
n/2 ≥ -3
Multiply by 2.
n ≥ -6.
