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Neporo4naja [7]
3 years ago
5

What is the gcf of 42 and 154

Mathematics
1 answer:
Assoli18 [71]3 years ago
4 0
The greatest common factor is 2
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Jim, Carla and Tomy are members of the same family. Carla is 5 years older than Jim. Tomy is 6 years older than Carla. The sum o
Blizzard [7]

We are given these three people age below:

  • Jim's age
  • Carla's age
  • Tomy's age

We define the age of Jim as any variable, because the problem doesn't give any specific age. I will define Jim's age as x.

  • Jim's age = x

Next, Carla is 5 years older than Jim. That means if Carla is 5 years older, her age would be x+5.

  • Carla's age = x+5

Then Tomy is 6 years older than Carla. That means the age would be 6+(x+5).

  • Tomy's age = 6+(x+5)

The sum of their three ages is 31 years old. That means we add all these ages and equal to 31.

\large{x + x + 5 + 6 + x + 5 = 31}

Combine like terms and solve for x.

\large{3x + 16 = 31}  \\  \large{3x = 31 - 16} \\  \large{3x = 15} \\  \large{x = 5}

Then we substitute the value of x in ages to find these three people ages.

  • Jim's age = x = 5
  • Carla's age = x+5 = 5+5 = 10
  • Tomy's age = 6+(x+5) = 6+(5+5) = 6+10 = 16.

Answer

  • Jim's age = 5
  • Carla's age = 10
  • Tomy's age = 16
4 0
3 years ago
Use the diagram shown. If BC = 14, AB = 11, and the perimeter of triangle ABC is 39, then what is the value of BD?
RUDIKE [14]

Answer:

BD=5.5

Step-by-step explanation:

11 divided by 2 gives you the answer

7 0
3 years ago
5 1/3 times x=2/3<br> What is x?
Alla [95]
I think the answer would be the 0.039.
7 0
3 years ago
Read 2 more answers
Suppose we want to choose 3 letters, without replacement, from the 4 letters A, B, C, and D.
ioda

Answer:A) 24 waysB) 4 waysStep-by-step explanation:a) permutation occurrs when order of choices matters.N = 4P3 = 4!/(4-3)! = 4!/1!N = 24 waysb) combination occurs when order of choices doesn't matter.N = 4C3 = 4!/3!(4-3)! = 4!/3!(1!)N = 4 ways

Step-by-step explanation:

a) permutation occurrs when order of choices matters.N = 4P3 = 4!/(4-3)! = 4!/1!N = 24 waysb) combination occurs when order of choices doesn't matter.N = 4C3 = 4!/3!(4-3)! = 4!/3!(1!)N = 4 ways(hope this helps:)

3 0
2 years ago
Question is in the picture.
love history [14]
A = lw + lw
A = (2)(11) + (2)(3)
A = 22 + 6
A = 28 yd²
7 0
3 years ago
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