Invested amount (P0 = £6000.
Rate of interest (r) = 3.4% = 0.034.
We know compound interest formula
A = P(1+r)^t
We need work out the value of his investment per year.
So, we need to plug t=1 and plugging values of P and r in the formula above, we get
A = 6000(1+0.034)^1
A = 6000(1.034)
A = 6204.
<h3>Therefore, the value of his investment per year is £ 6204.</h3>
Now, we need to work out the value of his investment after 3 years.
So, we need to plug t=3.
A = 6000(1+0.034)^3
A = 6000(1.034)^3
1.034^3=1.105507304
A = 6000 × 1.105507304
A = 6633.04
<h3>Therefore, the value of his investment after 3 year is £ 6633.04.</h3>
Mark you want me to tell him I can send you a photo of the photo you sent you send you
Answer:
m=-7/9
Step-by-step explanation:
PEMDAS
P- none
E- none
M- none
D- (3/1/3=1)
AS- 9-1+1=9
The answer is A.
Answer:
Rosaria purchased 50 bracelets and 70 necklaces
Step-by-step explanation:
Let the number of bracelets be b and the number of necklaces be n
b + n = 120 •••••(i)
Secondly;
10b + 11n = 1270 ••••(ii)
Total cost of b bracelets at 10 per 1 is 10b
Total cost of n bracelets at 11 per 1 is 11n
Adding both gives 1270
From i, b = 120-n
Substitute this into ii
10(120-n) + 11n = 1270
1200 - 10n + 11n = 1270
n = 1270-1200
n = 70
b = 120-n
b = 120-70
b = 50
