Can u help I am terrible at ordering numbers

Mathematics

1 answer:

ddd [48]3 years ago

4 0

OK so it's telling us to order it from least to greatest, WHICH MEEAANNS we start with the lowest possible number listed. ( I'm gonna turn the fractions into decimals just to make this easier. )

SO, we have:

-1.8 -- 1 -- 1.4 -- 1.9 -- -1.25

Ofc first we start with the negative numbers.

-1.8 and -1.25

( We're just gonna add an extra zero to 1.8 so we can see which is less )

SO, which is less -1.80 or -1.25

NOW REMEMBER negative numbers are different from positive, they get ranked in the opposite way. WHICH MEANS -1.80 is LESS than -1.25 BECAUSE -1.80 is farther from 0 than -1.25 is. Next is the positive numbers:

1 -- 1.4 -- 1.9

Now, this is the easy part. 1 is the least out of the positive numbers listed, then 1.4 then 1.9! Which makes the order:

-1.8 ---- -1.25 ---- 1 ---- 1 2/5 ---- 1 9/10

You might be interested in

1: Create a single variable linear equation that has no solution. Solve the equation algebraically to prove that it does not hav

OLga [1]

Answer:

(1) y=C, $C\neq0$

(2) x=C

(1) y=0

Step-by-step explanation:

For the linear equation, the power on the solitary variable must be 1.

When the graph of a function crosses/ touches the x-axis than the equation has solution/solutions otherwise it does not has a solution.

When it touches/cresses the x-axis for infinite times then it will have an infinite number of solutions.

(1) The linear equation y-C=0, where y is a variable and C is a non-zero constant, $C \neq 0$ , has the graph parallel to the x-axis. It has no solution as the graph will never cross/touch the x-axis.

Algebraically, in linear equation y-C=0, is independent of x, so there is no value of x for the solution to be exist.

(2) The linear equation x-C=0, where x is a variable and C is a constant, has one solution.

The solution for the equation is

x-C=0

$\Rightarrow x=C$ , where $C\neq0$ .

(3) The linear equation y=0, where y is a variable, has the graph coinciding with the x-axis. So, it has infinitely many solutions.

Algebraically, in linear equation y=0, is independent of x, so for all value of x, the given equation is zero. Hence, there are infinitely many solutions.

3 0

3 years ago

Please help me idk this

Sergio [31]

First take the fractions and find their common denominator:
$\frac{1}{2}$ x 4 = $\frac{4}{8}$

Now you can add the fractions:
$\frac{4}{8} + \frac{1}{8} = \frac{5}{8}$

Now add your whole numbers and the fraction:
1+1= 2 >> 2+ $\frac{5}{8}$ = 2 $\frac{5}{8}$ yards

Now subract 2 $\frac{5}{8}$ from 5:
5-2 $\frac{5}{8}$ =2 $\frac{3}{8}$ yards