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Dafna1 [17]
3 years ago
12

Work out the equation y=2x+7

Mathematics
1 answer:
lina2011 [118]3 years ago
8 0
Y=2x+7 is already in its simplest form. It can be used to graph.
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The sum of 5 and a certain number, x, is tripled. Write an expression for the resulting number.
Alja [10]
3 (5+x) You tripled 5+x ~JZ
7 0
3 years ago
If f(x) = 3x - 12, what is f(2)?<br> -6<br> -18<br> 18<br> 6
dusya [7]

Answer: -6

Explanation: In this problem, we're given the function f(x) = 3x - 12 and we're asked to find f(2).

To find f(2) or the value of the function when <em>x </em>equals 0, we simply substitute 2 in for <em>x</em> in our function. So we have f(x) = 3(2) - 12 or 6 - 12 which equals -6.

So f(2) or the value of the function when <em>x </em>equals 2 is -6.

4 0
3 years ago
Read 2 more answers
I’m confused on this one
Anna11 [10]
The answer is (-5,3)

3 0
3 years ago
What is the surface area of a cylinder with base radius 4 and height 5
AleksAgata [21]

Answer:

226.08

Step-by-step explanation:

Atop = (3.14)(4)²

= 50.24

Abottom = Atop = 50.24

Aside = C x H

C = 2πr

   = 2(3.14)(4)

   = 25.12

25.12 * 5

= 125.6

125.6 + 50.24 + 50.24

= 226.08

8 0
4 years ago
Laura and Philip each fire one shot at a target. Laura has probability 0.4 of hitting the target, and Philip has probability 0.1
Pepsi [2]

Answer:

(i) 0.46, (ii)0.42, and (iii)0.143

Step-by-step explanation:

Let p be the probability of hitting the target and q be the probability of missing the target by Laura.

Given that p=0.4\;\cdots (1)

As Laura either hit or miss the target, so p+q=1.

\Rightarrow q=1-p=0.6 \; \cdots (2)

Again, let r be the probability of hitting the target and s be the probability of missing the target by Philip.

Here, r=0.1\;\cdots (3)

Similarly, \Rightarrow s=1-r=0.9\;\cdots (4)

(i)The probability that the target is hit means that the target is not missed by both, either of one or both hit the target.

=1-(probability of missing the target by both)

=1-qr [from equation (2) and (4) ]

=1-0.6\times 0.9

=1-0.54

=0.46

(ii) The probability that the target is hit by exactly one shot means either of one hit the target.

=Hit by Laura and missed by Philip or hit by Philip and missed by Laura

=0.4\times 0.9+0.1\times 0.6 [from equations (1),(4) and (3),(2)]

=0.36+0.06

=0.42

(iii)Given that the target was hit by exactly one shot, so, the given probability is 0.42 [from (ii) part]

No, the probability that the target was hit by Philip = probability of hitting the target by Philip and missing the target by Laura

=0.1\times 0.6 [from equations (3) and (2)]

=0.06

So, the probability of hitting the target by Philip

=\frac {0.06}{0.42}

=\frac {1}{7}

=0.143 (approx)

6 0
3 years ago
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