Answer:
The genotypic frequency = 1:1
The phenotypic frequency = 1:1
Explanation:
Given that:
The allele → R = Red beetles
The allele → B = Blue beetles
Since the gene color shows a codominant allele
The Red Beetle = RR
The blue beetles will be = BB
The heterozygous beetle will be = RB
∴
The punnet square showing the crossing of RB × RR is:
                 R                   B
R                RR               RB
R                RR               RB
The result shows that we have two red beetles and two heterozygous beetles.
Hence;
The genotypic frequency = 1:1
The phenotypic frequency = 1:1
 
        
             
        
        
        
I think you wrote this wrong? Is it not round rr vs wrinkled RR?? I'll answer it with that assumption:
You are crossing a rr with an RR:
You only get Rr back so they will phenotypically be all wrinkled
If you are crossing rr with an Rr (so a heterozygote wrinkled):
50% will be Rr (wrinkled)
50% will be rr (round)
See my picture for the Punnett Squares for both answers!
 
        
        
        
Answer:
<em>The correct option is B) Scientific paradigm</em>
Explanation:
The scientific paradigm focuses on the infection and the microorganism for the occurrence of the infection. A scientific paradigm also refers to the treatment of these infections through pharmaceutical or surgical approaches. Hence, option B is correct.
Other options, like option A, is not correct because a holistic paradigm focuses on the connection between the mind, body and the soul. Option C is false because the analytical paradigm is not a part of the major health belief system. 
 
        
             
        
        
        
A makeshift increment in the squirrel proliferation rate.