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Olenka [21]
3 years ago
7

Please help and thank you

Mathematics
1 answer:
Anna11 [10]3 years ago
3 0
2 servings because one serving is 4%, so you would need would need to double that, or multiply it by two.
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What is the area of the figure below?
Scorpion4ik [409]

Answer:

rectangle: 30 in^2

triangle:  12 in^2

composite: 42 in^2

Step-by-step explanation:

area of a rectangle: length times width

area of a triangle: \frac{AB}{2}

composite area: break the area up by shapes you can find the area of, then add it back together

3 0
3 years ago
What is the radius of a circle that has a diameter of 199
wolverine [178]

Answer:

99.5

Step-by-step explanation:

Radius = Diameter/2

199/9

=99.5metres

6 0
2 years ago
Wendy wants to show people how medicines that doctors use now would have been helpful during the Civil War
Soloha48 [4]

Answer:

D

Step-by-step explanation:

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3 years ago
In 2 yrs time ella will be twice the age she was 5 yrs ago. how old is she now?
chubhunter [2.5K]
8 because 2 times 5 is ten
7 0
3 years ago
Heeeeeelllllllllppppppppppppppppp mmmmmmmmeeeeeeeeeeee!!!!!!!!!!!!!!!!!!!!!!!!!
Karo-lina-s [1.5K]

Yes it is possible for a geometric sequence to not outgrow an arithmetic one, but only if the common ratio r is restricted by this inequality: 0 < r < 1

Consider the arithmetic sequence an = 9 + 2(n-1). We start at 9 and increment (or increase) by 2 each time. This goes on forever to generate the successive terms.

In the geometric sequence an = 4*(0.5)^(n-1), we start at 4 and multiply each term by 0.5, so the next term would be 2, then after that would be 1, etc. This sequence steadily gets closer to 0 but never actually gets there. We can say that this is a strictly decreasing sequence.

If your teacher insists that the geometric sequence must be strictly increasing, then at some point the geometric sequence will overtake the arithmetic one. This is due to the nature that exponential growth functions grow faster compared to linear functions with positive slope.

8 0
3 years ago
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