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3 years ago

Which exponential function is equivalent to the logarithmic equation below: log 784=a

Mathematics

2 answers:

Sedbober [7]3 years ago

7 0

You have no exponential functions listed to choose from, but in this problem it is understood that the base of the log is 10 because it is not stated otherwise and a base of 10 is the "norm" for logs. So rewritten with that in mind, you have log base 10 (784)=a. In exponential form, that looks like this: 10^a=784. You could solve for a by typing in "log(784)" into your calculator to get that the exponent is equal to 2.894316063. If you raise 10 to that power you get 784.

ivanzaharov [21]3 years ago

4 0

Answer:

10^a=784

Step-by-step explanation:

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<u>Combined Ratio</u>

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2 years ago

Write an equation of the perpendicular bisector of the segment with endpoints G 9,8       and H 3,2      .

Norma-Jean [14]

Answer:

y = -x + 11

Step-by-step explanation:

The equation of a straight line is is given by:

y = mx + b; where m is the slope and b is the y intercept

The equation of the line joining G(9, 8) and H(3, 2) is given as:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-8=\frac{2-8}{3-9}(x-9)\\\\y-8=x-9\\\\y=x-1$

The perpendicular bisector of the line joining G(9, 8) and H(3, 2) is perpendicular to the line joining G(9, 8) and H(3, 2) and passes through the midpoint of line joining G(9, 8) and H(3, 2).

Let (x, y) be the midpoint of the line joining G(9, 8) and H(3, 2). Hence:

x = (9 + 3)/2 = 6

y = (8 + 2)/2 = 5

The midpoint = (6, 5)

Two lines are perpendicular if the product of their slopes is -1.

The line joining G(9, 8) and H(3, 2) has a slope of 1, hence, the slope of the perpendicular bisector would be -1.

This means that the perpendicular bisector has a slope of -1 and passes through (6, 5). Using:

$y-y_1=m(x-x_1)\\\\y-5=-1(x-6)\\\\y-5=-x+6\\\\y=-x+11$

The equation of the perpendicular bisector is y = -x + 11

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antoniya [11.8K]

Answer:

Step-by-step explanation:

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3 years ago

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